The number of presale tickets sold is 271
<em><u>Solution:</u></em>
Let "p" be the number of presale tickets sold
Let "g" be the number of tickets sold at gate
<em><u>Given that, total of 800 Pre-sale tickets and tickets at the gate were sold</u></em>
Therefore,
Presale tickets + tickets sold at gate = 800
p + g = 800 ------ eqn 1
<em><u>Given that, number of tickets sold at the gate was thirteen less than twice the number of pre-sale tickets</u></em>
Therefore,
Number of tickets sold at gate = twice the number of pre-sale tickets - 13
g = 2p - 13 ------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
Substitute eqn 2 in eqn 1
p + 2p - 13 = 800
3p -13 = 800
3p = 800 + 13
3p = 813
p = 271
Thus 271 presale tickets were sold
All of them
But if u had to pick one I would say addition or subtraction
Answer:
24
Step-by-step explanation:
9+6(2+3/6)
9+6(2+1/2)
2+1/2 = 2.5
9+6(2.5)
9+15
24
6 - 1/2z = 2/3
Steps
First, subtract 6 from both sides
6 - 1/2z - 6 = 2/3 - 6
Then, simplify
-1/2z = -16/3
Then, multiply both sides by -2
(-1/2z) (-2) = (-16/3) (-2)
Then, simplify
z = 32/3
3y + 2x =1
3y = - 2x + 1
y = - 2/3x + 1/3
slope : - 2/3
