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Marina86 [1]
3 years ago
13

A user car dealer brought a car for $12,000 and wants to sell it at a 15% profit. How much should he sell the car for?

Mathematics
2 answers:
abruzzese [7]3 years ago
7 0
The answer is $1,800
Snezhnost [94]3 years ago
6 0

Answer:

$13,800

Step-by-step explanation:

She sells the car for 115% of the value of the car, because she wants a 15% profit. 115% of 12000 is the same as 12000*1.15, since 115% is eqaul to 1.15. 12000*1.15 = 13800

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12=\fbox2\times\fbox2\times3\\\\16=\fbox2\times\fbox2\times2\times2\\\\28=\fbox2\times\fbox2\times7\\\\GCF(12;\ 16;\ 28)=\fbox2\times\fbox2=\boxed{\boxed{4}}
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3 years ago
There are 48 girls and 64 boys in the school choir. The choir teacher plans to arrange the students in equal rows. Only girls or
Lina20 [59]

Answer:

C.8

Step-by-step explanation:

48+64 = 112

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3 years ago
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Two​ shooters, Rodney and​ Philip, practice at a shooting range. They fire rounds each at separate targets. The targets are mark
Sedaia [141]

Complete Question

Answer:

a

  SE  = 0.66}

b

-3.29 <  \mu_1 - \mu_2 <  -0.70  

Step-by-step explanation:

From the question we are told that

  The sample size is  n  = 60

   The first sample mean is  \= x _1  =  8

    The second sample mean is   \= x _2  =  10

    The first variance is  v_1 =  0.25

    The first variance is  v_2 =  0.55

Given that  the confidence level is 95% then the level of significance is 5% =  0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the first standard deviation is  

     \sigma_1 =  \sqrt{v_1}

=>   \sigma_1 =  \sqrt{0.25}

=>   \sigma_1 =  0.5

Generally the second standard deviation is

     \sigma_2 =  \sqrt{v_2}

=>   \sigma_2 =  \sqrt{0.55}

=>   \sigma_2 =  0.742    

Generally the first standard error is

     SE_1  =  \frac{\sigma_1}{\sqrt{n} }

      SE_1  =  \frac{0.5}{\sqrt{60} }

     SE_1  =  0.06

Generally the second standard error is

     SE_2  =  \frac{\sigma_2}{\sqrt{n} }

      SE_2  =  \frac{0.742}{\sqrt{60} }

     SE_2  =  0.09

Generally the standard error of the difference between their mean scores is mathematically represented as    

      SE  =  \sqrt{SE_1^2 + SE_2^2 }

=>     SE  =  \sqrt{0.06^2 +0.09^2 }

=>     SE  = 0.66}

Generally 95% confidence interval is mathematically represented as  

      (\= x_1 -\= x_2) -(Z_{\frac{\alpha }{2} } *  SE) <  \mu_1 - \mu_2 <  (\= x_1 -\= x_2) +(Z_{\frac{\alpha }{2} } *  SE)

=> (8 -10) -(1.96 *  0.66) <  \mu_1 - \mu_2 <  (8-10) +(Z_{\frac{\alpha }{2} } *  0.66)  

=>  -3.29 <  \mu_1 - \mu_2 <  -0.70  

 

5 0
4 years ago
What is −5x + 4 for x = −5
Triss [41]

Answer:

29

Step-by-step explanation:

Given

- 5x + 4 ← substitute x = - 5 into the expression

= - 5(- 5) + 4 = 25 + 4 = 29

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3 years ago
Which is an example of a short-term investment?
katovenus [111]
Checking account is a short term investment
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