The rolls of the dice are independent, i.e. the outcome of the second die doesn't depend in any way on the outcome of the first die.
In cases like this, the probability of two events happening one after the other is the multiplication of the probabilities of the two events.
So, the probability of rolling two 6s is the multiplication of the probabilities of rolling a six with the first die, and another six with the second:

Similarly,

Actually, you can see that the probability of rolling any ordered couple is always 1/36, since the probability of rolling any number on both dice is 1/6:

Nine million, four hundred thousand, twenty three9
Answer: Ix - 5I ≥ 5.
Step-by-step explanation:
We want the set:
[0, 10]
to be the solution of:
Ix - bI ≤ c
So we need to find the values of c and b.
The first step is to find the middle point in our segment.
We can do that by adding the extremes and dividing it by 2.
M = (10 + 0)/2 = 5
And we also want to find half of the difference between the extremes, this is:
D = (10 - 0)/2 = 5.
Now, this set will be the set of solutions of:
Ix - MI ≥ D
Then in our case, we have:
Ix - 5I ≥ 5.
so we have that b = 5, and c = 5.