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3 years ago

Pls help I need it can you answer this question for me Evaluate 8^8/3 =

Mathematics

1 answer:

zubka84 [21]3 years ago

4 0

The answer for 1 is 2^8

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By system of substitution solve<br><br> y= -3x-5<br> y=4

Musya8 [376]

4 = -3x-5
3x = -9
x = -3

7 0

4 years ago

Brian has reduced his cholesterol level by 14% after his last check up. If his original level was 200, what is his cholesterol l

Alex_Xolod [135]

Answer:

228

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What is the coeffieent of (x^4)(y^4) in the expansion of (x+y)^8

kap26 [50]

ANSWER

The coefficient is 70.

EXPLANATION

The given binomial expression is

$(x+y)^8$

The specific term of a binomial expansion can be determined using the formula,

$T_{r+1}= nC_ra^{n-r}b^r$
where

$n=8,r=4,a=x,b=y$

We substitute these values into the formula to get,

$T_{4+1}= 8C_4x^{8-4}y^4$

We simplify to get,

$T_{5}= 70x^{4}y^4$

Hence the coefficient is 70.

4 0

3 years ago

This is the easiest question

Arturiano [62]

Answer: $3\dfrac{2}{6}\ h$

Step-by-step explanation:

Given

Rami practices his saxophone for $\frac{5}{6}$ hour on 4 day each week

So, for a week she practices around

$\Rightarrow \dfrac{5}{6}\times 4\\\\\Rightarrow \dfrac{20}{6}$

Converting it into mixed fraction

$\Rightarrow \dfrac{20}{6}=\dfrac{18+2}{6}\\\\\Rightarrow 3\dfrac{2}{6}\ h$

5 0

3 years ago

Find the inertia tensor for an equilateral triangle in the xy plane.

ivanzaharov [21]

Find the inertia tensor for an equilateral triangle in the xy plane. Take the mass of the triangle to be M and the length of a side of the triangle to be b. Express your answer below as pure numbers in units of Mb^2. Place the origin on the midpoint of one side and set the y-axis to be along the symmetry axis.

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3 years ago