Answer:
<JIL and <MLI
Step-by-step explanation:
Im looking for the same answer if anyone tell can you let me know
So for a linear line to be parallel to another line, they have to have the same slopes. The given line has a slope of -.75
If we use the point slope formula, which is y - y1 = m( x - x1 ) we can plug in the slope and the point that the line must go through to get the new line.
y - 0 = -.75( x - 8 )
y = -0.75x + 6
The equation of the line that is parallel to y = -0.75x and passes through (8,0) is
y = -0.75x + 6
Answer:(x-3)=-(y-5)=z
Step-by-step explanation:
Given
the point through which line passes is (3,5,0)
so we need a vector along the line to get the equation of line
It is given that line is perpendicular to both i+j & j+k
therefore their cross product will give us the vector perpendicular to both
v=(i+j)\times (j+k)=i-j+k
therefore we get direction vector of line so we can write
=t
i.e.
x=t+3,y=-t+5,z=t