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3 years ago

13

Greg spent 6.4 hours working with his dad one Saturday. If his dad paid him$45.76, how much did Greg make per hour?

1 answer:

nordsb [41]3 years ago

6 0

Answer:

$7.15

Step-by-step explanation:

The best way to solve this is by crossing out the data you don't need so you're left looking at the key pieces to put the equation together. If his dad paid him $45.76 for 6.4 hours, then all you need to do is divide 45.76 by 6.4. (Hint: Use a calculator, it makes it ten times faster than trying to write it out!)

45.76 ÷ 6.4 = 7.15

So Greg made $7.15 an hour working with his dad.

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If x+9.8=14.7, what is the value of 8(x-3.7?

yulyashka [42]

First find X by subtracting 9.8 from 14.7
X should equal 4.9
than fill in the equation for x
8(4.9-3.7)
you then subtract in the parenthasis
getting the answer of 1.2
finally multiply 1.2x8
Your final answer is 9.6

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3 years ago

What is another way to group the factors (3x2)x5

Elza [17]

3*(2*5)
You're Wlecome,

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3 years ago

an item is regularly priced $70. it is now priced at a discount of 20% off the regular price. what is the price now?

AVprozaik [17]

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8 0

3 years ago

A 10-foot ladder is leaning against a vertical wall. If the bottom of the ladder is being pulled away from the wall at the rate

Alex777 [14]

Answer:

The area is changing at 15.75 square feet per second.

Step-by-step explanation:

The triangle between the wall, the ground, and the ladder has the following dimensions:

H: is the length of the ladder (hypotenuse) = 10 ft

B: is the distance between the wall and the ladder (base) = 6 ft

L: the length of the wall (height of the triangle) =?

dB/dt = is the variation of the base of the triangle = 9 ft/s

First, we need to find the other side of the triangle:

$H^{2} = B^{2} + L^{2}$

$L = \sqrt{H^{2} - B^{2}} = \sqrt{(10)^{2} - B^{2}} = \sqrt{100 - B^{2}}$

Now, the area (A) of the triangle is:

$A = \frac{BL}{2}$

Hence, the rate of change of the area is given by:

$\frac{dA}{dt} = \frac{1}{2}[L*\frac{dB}{dt} + B\frac{dL}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - B^{2}}*\frac{dB}{dt} + B\frac{d(\sqrt{100 - B^{2}})}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - B^{2}}*\frac{dB}{dt} - \frac{B^{2}}{(\sqrt{100 - B^{2}})}*\frac{dB}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - 6^{2}}*9 - \frac{6^{2}}{\sqrt{100 - 6^{2}}}*9]$

$\frac{dA}{dt} = 15.75 ft^{2}/s$

Therefore, the area is changing at 15.75 square feet per second.

I hope it helps you!

5 0

3 years ago

Mary is making pillows for her Life Skills class. She bought 2.5 yards of fabric. Her total cost was $15. What was the cost per

m_a_m_a [10]

Answer:$6/Yard

Step-by-step explanation:

You make it into an algebraic expression, 2.5x=15.

Then, you divide both sides by 2.5

2.5x=15, 2.5x/2.5 =x, 15/2.5=6.

x=6.

x represents the amount of dollars per yard.

3 0

3 years ago

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