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Scorpion4ik [409]
3 years ago
5

Find cotθ if θ terminates in Quadrant III and secθ = 2

Mathematics
2 answers:
Umnica [9.8K]3 years ago
6 0

Answer:

we have

secθ = 2

\frac{1}{cos θ}=2

Cosθ =\frac{1}{2 }

\frac{b}{h }=\frac{1}{2 }

b=1

h=2

p=\sqrt{2²-1} = \sqrt{3}

again

Cot θ=\frac{b}{p }

Cot θ=\frac{1}{ \sqrt{3}}

Cot θ=\frac{\sqrt{3}}{3}

It lies in Quadrant III cot is positive

Cot θ=\frac{\sqrt{3}}{3}

<u>b. (sqrt 3)/3</u>

Kipish [7]3 years ago
4 0

\small\mathfrak\pink{s} \small\mathfrak\purple{o} \small\mathfrak\blue{l}  \small\mathfrak\red{u}\small\mathfrak\green{t} \small\mathfrak\orange{i}\small\mathfrak\blue{o}  \small\mathfrak\red{n:-}

b. (sqrt 3)/3 ✓

\\  \\

<em>~ʆᵒŕ∂ཇꜱꜹⱽẻⱮë</em>

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