Answer:
GL, Gl, gL, and gl
Explanation:
The mom is glossy long haired. Since glossy (G) is dominant over to dull (g) and long hair (L) is dominant to short hair (l), the possible genotypes of the mom would be:
GGLL, GgLL, GGLl, or GgLl
The dad is dull and short haired, the genotype would be ggll.
GGLL x ggll
Progeny = all GgLl (all glossy long haired)
GgLL x ggll
Progeny = 8 GgLl, 8 ggLi (glossy long haired and dull long haired)
GGLl x ggll
Progeny = 8 GgLl, 8 Ggll (glossy long haired and glossy short haired)
GgLl x ggll
Progeny = 4 GgLl, 4 Ggll, 4 ggLl, 4 ggll (glossy long, glossy short, dull long, and dull short)
<em>Only a cross of ggll with GgLl produced the offspring that cover the phenotypic range shown in the illustration. Hence, the genotype of the mom is GgLl.</em>
The parental gametes produced by the mom would be; GL, Gl, gL, and gl
