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Sonbull [250]
3 years ago
5

What are the possible values of x if (4x - 5)^2=49? Check all that apply.a-4/5

Mathematics
1 answer:
MakcuM [25]3 years ago
7 0

Answer:

e i think

Step-by-step explanation:

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A school had 1,200 students last year and only 1,080 students this year. What was the percentage decrease in the number of stude
jeyben [28]
Answer: 10%

First off, you need to divide 1200 with 1080.

1200 - 1080 = 120.

Next, divide 120 with the original number.

120 / 1200 = 0.1

Then, multiply 0.1 with 100.

100 x 0.1 = 10

Finally, add a % at the end.

10 -> 10%

So in summary, your answer is 10%
8 0
3 years ago
20 points if you help me on this proublem
VMariaS [17]

Answer:

1) f(x) = x/8 - 7

2) f(x) = 1 - x/3

3) f(x) = 20 - 0.25x

4) f(x) = x + 7

Step-by-step explanation:

f^-1 = 8(x + 7)

x + 7 = y/8

x = y/8 - 7

f(x) = x/8 - 7

f^-1 = -3(x - 1)

y/-3 = x - 1

x = 1 - y/3

f(x) = 1 - x/3

f^-1 = 4(20 - x)

y/4 = 20 - x

x = 20 - y/4

f(x) = 20 - x/4

f(x) = 20 - 0.25x

f^-1 = x - 7

y = x - 7

x = y + 7

f(x) = x + 7

3 0
3 years ago
Help me solve for A and B!
expeople1 [14]
Here we have one large triangle with two smaller triangles drawn inside.  The two smaller triangles are similar.

Thus, a/12 = 12/16, or   a/12 = 3/4, or 4a=36, or a = 9.  

Find b in the same way:  b/20 = 9/12 (and so on).
6 0
4 years ago
What is the value of 5- 4/7
Lyrx [107]
Hello!

We will just do the math as shown below. We will use 4 7/7 to make the subtraction a bit easier.

4 7/7-4/7=4 3/7

Therefore, our answer is A) 4 3/7.

I hope this helps!
7 0
3 years ago
PLS help me with thisss:((((((​
lara31 [8.8K]

Answer:

C and B

Step-by-step explanation:

(6)

\frac{3x-7y}{8} × \frac{6}{3x-7y} ← cancel 3x - 7y on numerator and denominator

= \frac{1}{8} × \frac{6}{1} = \frac{6}{8} = \frac{3}{4} → C

(7)

\frac{6x}{x^2-9} ÷ \frac{8}{4x-12}

Factorise the denominators of both fractions

x² - 9 = x² - 3² = (x - 3)(x + 3) ← difference of squares

4x - 12 ← factor out 4 from each term

= 4(x - 3)

Then rewrite as

\frac{6x}{(x-3)(x+3)} ÷ \frac{8}{4(x-3)} ← cancel 8 and 4 by 4

= \frac{6x}{(x-3)(x+3)} ÷ \frac{2}{x-3}

• leave first fraction, change ÷ to × , turn second fraction ' upside down'

= \frac{6x}{(x-3)(x+3)} × \frac{x-3}{2} ← cancel x - 3 on numerator and denominator

= \frac{6x}{x+3} × \frac{1}{2} ← cancel 2 and 6 on numerator and denominator

= \frac{3x}{x+3} → B

8 0
3 years ago
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