All categories

3 years ago

Help Me Please I need to do this for school

Mathematics

2 answers:

NNADVOKAT [17]3 years ago

8 0

Answer:

3 hours

I hope its right

hodyreva [135]3 years ago

4 0

Answer:

He worked for 3 hours.

Step-by-step explanation:

you can solve this by muiltipling the amount of hours by the kilograms done in an hour.

You might be interested in

Raise c to the 8th power!

Agata [3.3K]

Answer:

c^8

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Not sure what to do here? Naomi has 50 red beads and white beads. The number of red beads is 1 more than 6 times the number of w

lorasvet [3.4K]

R + w = 50
r = 6w + 1

now we sub ..
6w + 1 + w = 50
7w + 1 = 50
7w = 50 - 1
7w = 49
w = 49/7
w = 7 <== white beads

r = 6w + 1
r = 6(7) + 1
r = 42 + 1
r = 43 <=== red beads

7 0

3 years ago

Factorise x^2/4-y^2/4

Nuetrik [128]

Answer:

$\large\boxed{\left(\dfrac{x}{2}-\dfrac{y}{2}\right)\left(\dfrac{x}{2}+\dfrac{y}{2}\right)=\dfrac{x-y}{2}\cdot\dfrac{x+y}{2}}$

Step-by-step explanation:

$\dfrac{x^2}{4}-\dfrac{y^2}{4}=\dfrac{x^2}{2^2}-\dfrac{y^2}{2^2}\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\=\left(\dfrac{x}{2}\right)^2-\left(\dfrac{y}{2}\right)^2\qquad\text{use}\ (a-b)(a+b)=a^2-b^2\\\\=\left(\dfrac{x}{2}-\dfrac{y}{2}\right)\left(\dfrac{x}{2}+\dfrac{y}{2}\right)=\dfrac{x-y}{2}\cdot\dfrac{x+y}{2}$

3 0

3 years ago

cho hàm số y = f(x) có đạo hàm liên tục trên R thỏa mãn 2f(2x)+f(1-2x) = 12x2 víu mọi x thuộc R . Phương trình tiếp tuyến của đồ

Nina [5.8K]

Answer:

ask in english

Step-by-step explanation:

then I can help u

6 0

3 years ago

A large home improvement store is considering expanding its selection of moving products, such as cardboard boxes and packing ta

fiasKO [112]

Answer:

The store can be 90% confident that the interval from 0.293 to 0.355 captures the proportion of all customers of this store who have moved in the past 5 years.

Step-by-step explanation:

The confidence interval provides a range of values (lower and upper bound) based on a certain confidence level at which the true proportion or mean value of a given sample mean or proportion exists. In the scenario above, the confidence level is 90% and the confidence interval is 0.293 to 0.355. Hence, we can be 90% confident that the true proportion of all customers of the store who have moved within the last five years exists within this interval.

8 0

2 years ago