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Sidana [21]
3 years ago
15

The temperature at 6:00 am was -12 Fahrenheit. The temperature increased by 1/2 Fahrenheit each hour for 6 hours. What was the t

emperature, in degrees Fahrenheit,at noon?
Mathematics
1 answer:
zlopas [31]3 years ago
6 0

Answer: -9°F

Step-by-step explanation:

From the question, we are told that the temperature at 6:00 am was -12 Fahrenheit and that the temperature increased by 1/2 Fahrenheit each hour for 6 hours.

The temperature, in degrees Fahrenheit, at noon would be:

= -12°F + 1/2(6)

= -12°F + 3°F

= -9°F

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Below are two parallel lines with a third line intersecting them. What is x
sleet_krkn [62]

Answer:

136=x

Step-by-step explanation:

When an angle is shown, the one opposite of it is equal to the forst equation. The bottom angles are equal to 360ñ so if you take 46x2=92. Subtract 92 by 360 to get 268. Divide it by 2 to get one of the bigger angles, which is 134 degrees. And as for the top, one angle on the bottom is equal to the same spot on the top. so, 136=x

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PQR is a right-angled triangle. PQ = 16 cm. PR = 8 cm. Calculate the length of
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SOLUTION:

PQR is a right-angle triangle.

Therefore, to solve this problem, we will use Pythagoras theorem which is only applicable to right-angle triangles.

Pythagoras theorem is as displayed below:

a^2 + b^2 = c^2

Where c = hypotenuse of right-angle triangle

Where a and b = other two sides of right-angle triangle

Now we will simply substitute the values from the problem into Pythagoras theorem in order to obtain the length of QR.

c = PQ = 16cm

a = PR = 8cm

b = QR = ?

a^2 + b^2 = c^2

( 8 )^2 + b^2 = ( 16 )^2

64 + b^2 = 256

b^2 = 256 - 64

b^2 = 192

b = square root of ( 192 )

b = 13.8564...

b = 13.86 ( to 2 decimal places )

FINAL ANSWER:

Therefore, the length of QR is 13.86 centimetres to 2 decimal places.

Hope this helps! :)
Have a lovely day! <3
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