HELP WILL GIVE BRANLIEST!!

Find the vertices and foci of the hyperbola with equation quantity x plus 1 squared divided by 225 minus the quantity of y plus

miss Akunina [59]

Answer:

The vertices are (-16,-5) and (14,-5)

The foci are (-26,-5) and (24,-5)

6 0

4 years ago

Which property was used to write the equation in step 2?

adelina 88 [10]

Answer:

A

Step-by-step explanation:

Given

5(x - 7) = 55, then using the distributive property, that is

a(b - c) = ab - ac, then

5x - 35 = 55

6 0

3 years ago

Read 2 more answers

Type the correct answer in each box. If necessary, round your answers to the nearest hundredth.

disa [49]

Answer:

Perimeter = 32.44 units

Area = 30 square units

Step-by-step explanation:

Given

Vertices

A(2,8), B(16,2) and C(6,2)

WE have to determine the lengths of all sides before finding the perimeter and area.

The formula of modulus is:

$d = \sqrt{(x_{2}- x_{1})^{2} +(y_{2}-y_{1})^{2}}\\AB=\sqrt{(16-2)^{2} +(2-8)^{2}}\\=\sqrt{(14)^{2} +(-6)^{2}}\\=\sqrt{196+36}\\ =\sqrt{232}\\=15.23\\\\BC=\sqrt{(6-16)^{2} +(2-2)^{2}}\\=\sqrt{(-10)^{2} +(0)^{2}}\\=\sqrt{100+0}\\ =\sqrt{100}\\=10\\\\AC=\sqrt{(6-2)^{2} +(2-8)^{2}}\\=\sqrt{(4)^{2} +(-6)^{2}}\\=\sqrt{16+36}\\ =\sqrt{52}\\=7.21\\\\$

So the perimeter is:

$Perimeter=AB+BC+AC\\=15.23+10+7.21\\=32.44\ units$

Using hero's formula,

$s=\frac{perimeter}{2}\\s=\frac{32.44}{2}\\ s=16.22\\Area=\sqrt{s(s-a)(s-b)(s-c)}\\=\sqrt{16.22(16.22-15.23)(16.22-10)(16.22-7.21)}\\=\sqrt{(16.22)(0.99)(6.22)(9.01)}\\=\sqrt{899.91}\\=29.99\ square\ units$

Rounding off will give us 30 square units ..

4 0

4 years ago

Consider randomly selecting a student at a large university, and let A be the event that the selected student has a Visa card an

poizon [28]

Answer:

We have that $B = 0.3$ .

So

$0.3 = b + (A \cap B)$

However, b is a probability, which means that it cannot be negative. So no, P(A ∩ B) cannot be 0.5. It can, at most, be 0.3.

Step-by-step explanation:

Event A:

Probability that a student has a Visa card.

Event B:

Probability that the student has a MasterCard.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student has a Visa card but not a MasterCard and $A \cap B$ is the probability that a student has both these cards.

By the same logic, we have that:

$B = b + (A \cap B)$

In this problem, we have that:

$A = 0.6, B = 0.3$

(a) Could it be the case that P(A ∩ B) = 0.5?

We have that $B = 0.3$ .

So

$0.3 = b + (A \cap B)$

However, b is a probability, which means that it cannot be negative. So no, P(A ∩ B) cannot be 0.5. It can, at most, be 0.3.

8 0

4 years ago

When you go to a restaurant you decide to give the waiter a 17% tip. What percentage of the bill do you pay?

san4es73 [151]

Answer:

You pay 117% of the bill

Step-by-step explanation:

1+x%

8 0

3 years ago