First, we start with the equation that the problem told us, which is:
R + 6 = 2 * (x + 6)
Then, we distribute the two:
R + 6 = 2x + 12
Now, we put R on its own side.
R = 2x +6
So, the answer must be C, 2x + 6
Answer: one solution
Step-by-step explanation:
CONCEPT:
- One solution is when the final variable would be able to find a solution.
- Infinite solution is when the equations result in 0=0, meaning any number will fit
- No solution is when the equation results in both sides on equal.
SOLVE:
Given
3/4x-7=3(1/6x+1)
Expand Parenthesis
3/4x-7=1/2+3
Multiply both sides by the LCM of fractions (Least Common Multiple)
4(3/4x-7)=4(1/2x+3)
3x-28=2x+12
Subtract both sides by 2x
3x-28-2x=2x+12-2x
x-28=12
Add both sides by 28
x-28+28=12+28
x=40
Since we are able to get exactly one solution, there is only one solution.
Hope this helps!! :)
Please let me know if you have any quesionts
<h3>Given</h3>
- arc AB of circle O is 1/4 of the circumference
- radius of circle O is 5
- pi is 3.14
<h3>Find</h3>
<h3>Solution</h3>
Since arc AB is 1/4 of the circumference, the central angle AOB will be 1/4 of a circle, so π/2 in radians. The area of a sector is given by
... A = (1/2)r²·θ
where θ is the central angle in radians and r is the radus.
The area is ...
... A = (1/2)·5²·π/2 = 25π/4
... A ≈ 19.625
The area of the sector is about 19.63 square units.
To solve for the quadratic equation 9x² = 4, we need to recall that the difference between two square can be expressed as the product of their sum and difference or (a² - b²) = (a + b)(a - b).
Thus, we have
9x² = 4
9x² - 4 = 0
(3x)² - (2)² = 0
(3x + 2)(3x - 2) = 0
We now have two linear equations:
3x + 2 = 0 | 3x - 2 = 0
3x = -2 | 3x = 2
x = -2/3 | x = 2/3
Thus, x = +2/3 and -2/3.<span>
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