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dedylja [7]
3 years ago
12

Noo question djjddrf f f f f f

Mathematics
1 answer:
a_sh-v [17]3 years ago
6 0
Wow that’s so cool man
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Please help me with this its my last math question will give brainly for correct answer
Citrus2011 [14]

Answer:

64

Step-by-step explanation:

 

4 0
2 years ago
HELP ASAP WILL MARK BRAINLIEST
madreJ [45]

Answer:

who knows babe

Step-by-step explanation:

3 0
3 years ago
12 for 3 books ; 28 for 7
Gelneren [198K]
The answer is 4 because if u divide both equations by eachother you get 4
3 0
3 years ago
Check whether the relation R on the set S = {1, 2, 3} is an equivalent
kozerog [31]

Answer:

R isn't an equivalence relation. It is reflexive but neither symmetric nor transitive.

Step-by-step explanation:

Let S denote a set of elements. S \times S would denote the set of all ordered pairs of elements of S\!.

For example, with S = \lbrace 1,\, 2,\, 3 \rbrace, (3,\, 2) and (2,\, 3) are both members of S \times S. However, (3,\, 2) \ne (2,\, 3) because the pairs are ordered.

A relation R on S\! is a subset of S \times S. For any two elementsa,\, b \in S, a \sim b if and only if the ordered pair (a,\, b) is in R\!.

 

A relation R on set S is an equivalence relation if it satisfies the following:

  • Reflexivity: for any a \in S, the relation R needs to ensure that a \sim a (that is: (a,\, a) \in R.)
  • Symmetry: for any a,\, b \in S, a \sim b if and only if b \sim a. In other words, either both (a,\, b) and (b,\, a) are in R, or neither is in R\!.
  • Transitivity: for any a,\, b,\, c \in S, if a \sim b and b \sim c, then a \sim c. In other words, if (a,\, b) and (b,\, c) are both in R, then (a,\, c) also needs to be in R\!.

The relation R (on S = \lbrace 1,\, 2,\, 3 \rbrace) in this question is indeed reflexive. (1,\, 1), (2,\, 2), and (3,\, 3) (one pair for each element of S) are all elements of R\!.

R isn't symmetric. (2,\, 3) \in R but (3,\, 2) \not \in R (the pairs in \! R are all ordered.) In other words, 3 isn't equivalent to 2 under R\! even though 2 \sim 3.

Neither is R transitive. (3,\, 1) \in R and (1,\, 2) \in R. However, (3,\, 2) \not \in R. In other words, under relation R\!, 3 \sim 1 and 1 \sim 2 does not imply 3 \sim 2.

3 0
3 years ago
in how many ways can alice distribute 12 apples to 3 children? each child has to have AT LEAST 1 apple.
elena-s [515]

Answer:

I think it would be 4 apples for each of them !

Step-by-step explanation:

its division. you had to do 12 ÷ 3

5 0
3 years ago
Read 2 more answers
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