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ankoles [38]
3 years ago
15

Quadrilateral A'B'C'D' is the image of quadrilateral ABC D under a dilation.

Mathematics
1 answer:
Semenov [28]3 years ago
4 0

Answer:

Step-by-step explanation:

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Round it to 1 significant figure
balu736 [363]

Answer:

2 ( one significant figure)

Step-by-step explanation:

798/8 x 41 in order to express it in 1 significant figure

we will multiply the denominator and then divide both the numerator and denominator.

so,

798/328

798/328

2.453

now to one significant figure it will be  2

3 0
4 years ago
Help please it’s due tomorrowit would mean a lot
Ne4ueva [31]
Where is the pattern?
4 0
3 years ago
Evaluate the expression when a=-4 and x=5.<br> a- 1- 2x<br> help pls
ivolga24 [154]

Answer:

-15

Step-by-step explanation:

So it's a-1-2x.

rewrite as -4-1-(2*5)

-4-1-10

-4+-1-10

-5+-10

-15

5 0
3 years ago
Read 2 more answers
Final exam scores are normally distributed with a mean of 74 and a standard deviation of 6. Approximately, what percentage of fi
notka56 [123]

Answer:

81.86%

Step-by-step explanation:

We have been given that final exam scores are normally distributed with a mean of 74 and a standard deviation of 6.

First of all we will find z-score using z-score formula.

z=\frac{x-\mu}{\sigma}

z=\frac{68-74}{6}

z=\frac{-6}{6}=-1

Now let us find z-score for 86.

z=\frac{86-74}{6}    

z=\frac{12}{6}=2        

Now we will find P(-1<Z) which is probability that a random score would be greater than 68. We will find P(2>Z) which is probability that a random score would be less than 86.

Using normal distribution table we will get,    

P(-1

P(2>Z)=.97725  

We will use formula P(a to find the probability to find that a normal variable lies between two values.

Upon substituting our given values in above formula we will get,

P(-1

P(-1

Upon converting 0.81859 to percentage we will get

0.81859*100=81.859\approx 81.86

Therefore, 81.86% of final exam score will be between 68 and 86.  


3 0
3 years ago
What is 2+2x•13(14-2x)
ivolga24 [154]

184-24x this is answer first just distribute abs then combine like terms
6 0
3 years ago
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