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Gelneren [198K]
3 years ago
6

What is stage 2 of mitosis

Biology
1 answer:
Alenkasestr [34]3 years ago
7 0

Answer:

Metaphase

Explanation:

Metaphase is when the sister chromatids line up in the middle with fibers attached to each end.

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Identify how the deletion of a single nitrogen base in DNA can cause a harmful mutation in an organism.
ra1l [238]

Answer:

B. Nearly every amino acid translated after the error will create the wrong protein after the deletion of a base.

Explanation:

Generally, mutations occur in two ways: 1) a base replacement, where one base is replaced for another; 2) insertion or deletion, where a base is either incorrectly inserted or deleted from a codon.

When a nucleotide is wrongly inserted or deleted from a codon, the effects of this change can be extreme. An insertion or deletion can affect every codon in a particular genetic sequence.  For example, given the code:

GAU GAC UCC GCU AGG. It is the codes for the amino acids aspartate, aspartate, serine, alanine, and arginine. If the A in the GAU were to be deleted, the code would become GUG ACU CCG UAG G. It won't produce any right amino acid.

So, if the code becomes changes, it won't produce any amino acid or will produce the wrong amnio acid.

8 0
4 years ago
The following F2 phenotypic data was obtained from a Drosophila testcross using an F1 offspring. Assume red eye and brown body a
dmitriy555 [2]

Answer:

The genotype of the F1 was wy+/w+y.

Explanation:

One of the given options has a typo: the red eye-brown body offspring count should be 56 instead of 561.

<u>We have two genes with two alleles each:</u>

Red eyes (w+) is dominant over white eyes (w).

Brown body (y+) is dominant over yellow body (y).

The phenotypes of the F2 tesulting from a test cross (F1 x wy/wy) are:

  • wy+/ey (white-eye, brown body): 670
  • w+y/wy (red-eye, yellow body): 650
  • wy/wy (white-eye, yellow body): 38
  • w+y+/wy (red-eye, brown body 56

If the genes w and y are linked, two phenotypes in the F2 will be much more abundant than the other two. Recombination during meiosis is a rare event, so the most abundant phenotypes are the parentals (the ones present in the F1 parent).

Every individual in the offpsring has a <em>wy</em> chromosome, as this was the gamete inherited from the test cross individual.

In this case, the most abundant gametes are wy+ and w+y, so the genotype of the F1 was wy+/w+y.

Notice how when recombination occurs in the F1 parent, the recombinant gametes appear: wy and w+y+, which are the less abundant in the F2 progeny.

8 0
3 years ago
Cleaning products and household cleaners are mostly? A.Basic . Acidic C. Neutral D. none of the above
valkas [14]
B. Acidic
Hope this helps!!
8 0
3 years ago
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Based on what you know about the location of the earth in relation to the sun, why is this called the Goldilocks zone in other g
sladkih [1.3K]

Answer:

B

Explanation:

The distance of the Goldilocks zone ensures that water on the terrestrial planet is maintained in the liquid phase. This is because the distance from the star ensure it receives enough sunlight to keep the planet warm but not too hot that the water exists as vapor. Water in its liquid form is essential for maintaining life like here on earth.

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4 years ago
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Plz answer again will give brainlest you just gotta tell me how to do it
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Global warming causes increase level CO2
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