A]
D=R×t
d=5.8r
d2=5.1(r+7)
0.7r=35.7
r=51 mi/hr
thus the average speed on the outbound trip would be:
51+7=58 mi/hr
b]
let speed of fishing boat=x km/h
speed of cruise ship=(x+12.5) km/h
distance traveled by fishing boat=11.5×x=11.5x km
distance traveled by cruise ship=(x+12.5)×11=(11x+137.5) km
Total distance covered by the ships:
11.5x+11x+137.5=322
22.5x=322-137.5
22.5x=184.5
thus
x=184.5/22.5
x=8.2 km/h
The speed of fishing boat is 8.2 km/hr
Answer:
3
Step-by-step explanation:
Given:
4 Divide by 2 and add 1
Computation;
[4 / 2] + 1
Using BODMAS rule
⇒ [4 / 2] + 1
⇒ 2 + 1
3
First: Replace “x” with its known value. Since x = 3, plug it into the formula.
• F(3) = 6^3
Second: Solve the formula.
• 6^3 = 6 x 6 x 6 = 216
• F(3) = 216
