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Kipish [7]
3 years ago
10

The screen shot is in the file.... PLEASE HELPPP

Mathematics
1 answer:
jenyasd209 [6]3 years ago
4 0

Answer:

Option A: Madison, (1.2,-1.6) is the correct answer.

Step-by-step explanation:

Observing Madison's solution it can be seen that he has used elimination method to solve the system. If elimination method has to be used the first equation has to be multiplied by 4

4(2x-y) = 4(4)\\8x-4y = 16

While Madison has made mistake with sign of one term in equation 1 (he has written -8x instead of 8x)

So <u>Madison's solution is wrong. </u>

Tyler has used the substitution method to solve the system of equations and has done it correctly (Calculated value of y in terms of x from equation 1 and substituted in equation 2)

The value of x=1.2 is correct, we have to find the value of y

So,

Putting the value of x=1.2 we get,

y=2x-4\\y = 2(1.2)-4\\y = 2.4-4\\y= -1.6

The solution of given system of equations is (1.2,-1.6)

Hence,

Option A: Madison, (1.2,-1.6) is the correct answer.

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What Is the medían number of books<br>​
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4. Find the derivative of sin x from first principle. <br><br>​
olga_2 [115]

Step-by-step explanation:

\text{By First Principle,}

\begin{align}\dfrac{d}{dx}\sin x&=\lim_{h\to0}\frac{\sin(x+h)-\sin x}{h}\\&=\lim_{h\to0}\frac{\sin x\cos h+\sin h\cos x-\sin x}{h}\\&=\lim_{h\to0}\left(\frac{\cos h-1}{h}\cdot\sin x\right)+\lim_{h\to0}\left(\frac{\sin h}{h}\cdot\cos x\right)\\&=\sin x\cdot\left(\lim_{h\to0}\frac{\cos h-1}{h}\right)+\cos x\cdot\lim_{h\to0}\left(\frac{\sin h}{h}\right)\\&=\sin x\cdot 0+\cos x\cdot1\\&=\cos x\end{align}

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3 years ago
The width, y, of a rectangle with a fixed area varies inversely with its length, x. The width is 3 inches when the length is 14
IrinaVladis [17]

Answer:

y = 1.4

Step-by-step explanation:

Given

y = width

x = length

y = 3;\ when\ x = 14

Required

Find y when x = 30

Being an inverse variation, we have:

y\ \alpha\ \frac{1}{x}

Convert the variation to an equation

y = \frac{k}{x}

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Make k the subject to solve for k

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k = 14 * 3

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To solve for y when x = 30

Substitute 30 for x and 42 for k in k = xy

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Make y the subject

y = \frac{42}{30}

y = 1.4

6 0
3 years ago
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