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3 years ago

What is the solution for x in the equation? -x + 3/7 =2x -25/7

Mathematics

1 answer:

guapka [62]3 years ago

3 0

Answer:

x = 4/3 is your answer

Step-by-step explanation:

Hope this helps!!

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Please help and Solve for x.

Serhud [2]

Answer:

$tan70 = \frac{opp}{adj} \\ \: \: = \frac{15}{x } \\ \\ x = \frac{15 }{tan70 } \\ \\ = \frac{15}{2.747} \\ \\ = 5.46$

since 5.46 is equal to 5.5...

I think the answer is the first one

7 0

3 years ago

this probability distribution shows the typical distribution of pitches thrown to a batter in a given at-bat in a baseball game.

Otrada [13]

Answer = 9/10

Explanation:

Add up all the frequencies along the bottom row: 15+20+40+15+10 = 100

There are 100 pitches total. Ten of which occurs when the pitcher throws 5 times at the batter, as shown in the far right-most column. This means 100-10 = 90 occurrences happen when the pitcher throws 4 or fewer pitches to the batter.

The probability your teacher wants is therefore 90/100 = 9/10. This answer is in fraction form. It is equivalent to the decimal form 0.9

3 0

3 years ago

what is the approximate distance from one corner of the soccer field to the opposite corner 60 yards, 100 yards

aalyn [17]

Answer:

Using Pythagorean theorem:

Diagonal = sqrt( 60^2 + 100^2) = 116.62

Hope this helps!

7 0

3 years ago

A company with a fleet of 150 cars found that the emissions systems of only 4 out of the 25 they tested failed to meet pollution

salantis [7]

Answer:

No, there is no strong evidence that the percentage of the fleet out of compliance is different from their initial thought.

Step-by-step explanation:

We are given that a company with a fleet of 150 cars found that the emissions systems of only 4 out of the 25 they tested failed to meet pollution control guidelines.

The company initially believed that 30% of the fleet was out of compliance.

Let p = percentage of the fleet that was out of compliance.

SO, Null Hypothesis, $H_0$ : p = 30% {means that the percentage of the fleet out of compliance is same as their initial thought}

Alternate Hypothesis, $H_A$ : p $\neq$ 30% {means that the percentage of the fleet out of compliance is different from their initial thought}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = percentage of the fleet out of compliance = $\frac{4}{25}$ = 16%

n = sample of systems tested = 25

So, test statistics = $\frac{0.16-0.30}{{\sqrt{\frac{0.16(1-0.16)}{25} } } } }$

= -1.909

The value of the test statistics is -1.909.

Since in the question we are not given with the level of significance at which hypothesis can be tested, so we assume it to be 5%. Now at 5% significance level, the z table gives critical values between -1.96 and 1.96 for two-tailed test.

Since our test statistics lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the percentage of the fleet out of compliance is same as their initial thought.

3 0

3 years ago

1. -6(9 - 9v) 2. -8(b + 3) 3. -(3x - 9)

never [62]

Answer:

1) =54v−54

−6(9−9v)

=(−6)(9+−9v)

=(−6)(9)+(−6)(−9v)

=−54+54v

=54v−54

2) =−8b−24

−8(b+3)

=(−8)(b+3)

=(−8)(b)+(−8)(3)

=−8b−24

3) −(3x−9)

=−3x+9

Step-by-step explanation: Hope this help :D

5 0

3 years ago