<span>x - 3/(x - 4) + 4 = 3 × x/3
</span>
<span><span>x^2−19/</span><span>x−4</span></span>=x
<span>Step 1: Multiply both sides by x-4.
</span><span><span><span>x^2</span>−19</span>=<span><span>x^2</span>−<span>4x
</span></span></span><span><span><span><span>x^2</span>−19</span>−<span>x^2</span></span>=<span><span><span>x^2</span>−<span>4x</span></span>−<span>x^2</span></span></span><span>(Subtract x^2 from both sides)
</span><span><span>−19</span>=<span>−<span>4x</span></span></span>
<span><span>−<span>4x</span></span>=<span>−19</span></span><span>(Flip the equation)
</span><span><span><span>−<span>4x</span></span><span>/−4</span></span>=<span><span>−19</span><span>/−4 </span></span></span>(Divide both sides by -4)<span>Answer.
x=<span>19/4
</span></span><span>Check answers. (Plug them in to make sure they work.)</span>
Answer:
Step-by-step explanation:
Distance=400+200=600km
diplacement=x 200-0km=200km
total distance travelled=400+400=800km
Answer:
30.7 km
Step-by-step explanation:
The distance between the two fires can be found using the Law of Cosines. For ΔABC in which sides 'a' and 'b' are given, along with angle C, the third side is ...
c = √(a² +b² -2ab·cos(C))
The angle measured between the two fires is ...
180° -(69° -35°) = 146°
and the distance is ...
c = √(11² +21² -2(11)(21)cos(146°)) ≈ √945.015
c ≈ 30.74
The straight-line distance between the two fires is about 30.7 km.
I know this is not an answer but if your having trouble with this there is a website called Desmos all you do is type in the equation for the graph and it gives you the answer
