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Lynna [10]
3 years ago
10

The height of an object dropped from a tower is 64 feet above the ground after t seconds can be modeled with the function h = 16

x2 + 64. which description is true about the the possible domain values of this real world function
Mathematics
1 answer:
gladu [14]3 years ago
4 0

Answer:

144 ft

Step-by-step explanation:

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100 points and brainliest! geometry<br><br> please explain :)<br><br> thanks for reading this :)
scoundrel [369]

Hellooooo!! Marie Here!!!

The answer is here:

The value of "x" is 9

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7 0
3 years ago
Choose the correct simplification of the expression (7x − 3)(4x^2 − 3x − 6).
-BARSIC- [3]
Distribute
(7x)(4x^2-3x-6)+(-3)(4x^2-3x-6)=
28x^3-21x^2-42x-12x^2+9x+18=
28x^3-21x^2-12x^2-42x+9x+18=
28x^3-33x^2-33x+18

D is the correct answer
4 0
3 years ago
Paisley is going to invest in an account paying an interest rate of 3.8% compounded monthly. How much would Paisley need to inve
victus00 [196]

Answer:

Step-by-step explanation:

Use the formula

A(t)=P(1+\frac{r}{n})^{nt}

Fill in the info we are given:

1210=P(1+\frac{.038}{12})^{(12)(6)} and

1210=P(1.003166667)^{72} and

1210 = P(1.255632915) so

P = $964

3 0
3 years ago
HELP PLEASE !!!!! A person is on the top of a 60 m tall building. They throw a coin up into the air with a velocity of 15 m/s. H
Anon25 [30]

Answer:

-24.8 m/s

Step-by-step explanation:

Given:

y₀ = 60 m

y = 40 m

v₀ = 15 m/s

a = -9.8 m/s²

Find: v

There are three constant acceleration equations we can use:

y = y₀ + v₀ t + ½ at²

v = at + v₀

v² = v₀² + 2a(y − y₀)

We aren't given the time, so we need to use the third equation, which is independent of time:

v² = v₀² + 2a(y − y₀)

Plug in the values:

v² = (15 m/s)² + 2(-9.8 m/s²) (40 m − 60 m)

v² = 617 m²/s²

v ≈ ±24.8 m/s

Since the coin is on the way down, the velocity is negative.  So v = -24.8 m/s.

8 0
3 years ago
(6.4×10^4)+(5.2×10^4)
Volgvan

6.4(104)+5.2(104)

=(6.4)(10000)+5.2(104)

=64000+5.2(104)

=64000+(5.2)(10000)

=64000+52000

=116000


7 0
3 years ago
Read 2 more answers
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