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3 years ago

Which set of numbers are possible side lengths for a right triangle?

Mathematics

1 answer:

SCORPION-xisa [38]3 years ago

7 0

Answer:

6 8 10

Step-by-step explanation:

This is a simple explanation from online but basically the ratio between the numbers can add up. Any multiple of 3,4,5 triangles work.

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Which statements must be true regarding the two triangles? Check all that apply. M M" O LMN - L"M"N" O LMN 2 L"M"N"

blagie [28]

Answer: The 1st, 2nd, and 5th one

Step-by-step explanation:

just did it

8 0

3 years ago

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Which equation could you use to solve for x in the proportion StartFraction 4 over 5 EndFraction = StartFraction 9 over x EndFra

4vir4ik [10]

Answer:

It is b :)

Step-by-step explanation:

5 0

3 years ago

Elissa needs 8.5 inches of thread to make a friendship bracelet. What is the maximum number of bracelets she can make with 40 in

Zepler [3.9K]

Answer:

Step-by-step explanation:

Elissa uses 8.5 inches of thread per bracelet.

She has 40 inches of thread.

To find the maximum number of bracelets she can make, we need to divide.

40 / 8.5 = 4.70588...

We cannot have an unfinished bracelet, so we have to round down.

She can make 4 bracelets with 40 inches of thread.

5 0

2 years ago

Read 2 more answers

The mean cost of domestic airfares in the United States rose to an all-time high of $385 per ticket (Bureau of Transportation St

saveliy_v [14]

Answer:

a)0.067

b)0.111

c)0.612

d)$687.28

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $385

Standard Deviation, σ = $110

We are given that the distribution of domestic airfares is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(domestic airfare is $550 or more)

P(x > 550)

$P( x > 550) = P( z > \displaystyle\frac{550 - 385}{110}) = P(z > 1.5)$

$= 1 - P(z \leq 1.5)$

Calculation the value from standard normal z table, we have,

$P(x > 550) = 1 - 0.933 = 0.067= 6.7\%$

b) P(domestic airfare is $250 or less)

$P(x \leq 250) = P(z \leq \displaystyle\frac{250-385}{110}) = P(z \leq -1.22)$

Calculating the value from the standard normal table we have,

$P( x \leq 250) = 0.111 = 11.1\%$

c))P(domestic airfare is between $300 and $500)

$P(300 \leq x \leq 500) = P(\displaystyle\frac{300 - 385}{110} \leq z \leq \displaystyle\frac{500-385}{110}) = P(-0.77 \leq z \leq 1.04)\\\\= P(z \leq 1.04) - P(z < -0.77)\\= 0.851 - 0.239 = 0.612 = 61.2\%$

$P(300 \leq x \leq 500) = 61.2\%$

d) P(X=x) = 0.03

We have to find the value of x such that the probability is 0.03.

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 385}{110})=0.03$

$= 1 -P( z \leq \displaystyle\frac{x - 385}{110})=0.03$

$=P( z \leq \displaystyle\frac{x - 385}{110})=0.997$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 385}{110} = 2.748\\x = 687.28$

Hence, the domestic fares must be $687.28 or greater for them to lie in the highest 3%.

7 0

3 years ago

3x + 2z - 4y - 6 + 4z + 7y

Anon25 [30]

Answer:

3x(2z+4z)+(−4y+7y)−6

Step-by-step explanation:

1 Collect like terms.

3x+(2z+4z)+(−4y+7y)−6

2 Simplify.

3x+(2z+4z)+(−4y+7y)−6

3x+6z+3y−6

5 0

3 years ago