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Ludmilka [50]
3 years ago
10

Bobby catches 8 passes in 3 football games . At this rate how many passes dose he catch in 15 games?

Mathematics
1 answer:
SashulF [63]3 years ago
3 0

Answer:

if bobby catches 8 passes a football game exactly then in 15 games he would have 40 passes

8=3        8x5=x    x=40

                          40 passes in 15 games.

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Round 4358 to the nearest thousand
Hitman42 [59]

Answer:

4,000

Step-by-step explanation:

You go to the thousand number and see if the hundred number is higher than 5, if not then its stays the same.

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3 years ago
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5. The internal dimension of a tank are 14m, 8m and 5m. How much water can be
EleoNora [17]

Answer:

560,000L

Step-by-step explanation:

Given data

L=14m

W=8m

H=5m

Volume= L*W*H

Volume= 14*8*5

Volume= 560 m^3

1m^3 = 1000L

560m^3 = x

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x= 560*1000

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3 years ago
Six times a number increased by 5
sergey [27]
I'm not quite sure what you asking here but if your asking how to answer it in "math terms" than I'll be happy to explain :)

So "times" means multiply and "increase" means add so righting this in math terms would be 
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7 0
4 years ago
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Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

  • J(2;5); K(1;1)

             => JK = \sqrt{(1-2)^{2} + (1-5)^{2}  } = \sqrt{(-1)^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • J(2;5); L(5;2)

             => JL = \sqrt{(5-2)^{2} + (2-5)^{2}  } = \sqrt{3^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • K(1;1); L(5;2)

             =>  KL = \sqrt{(5-1)^{2} + (2-1)^{2}  } = \sqrt{4^{2}+1^{2}  } = \sqrt{1+16}=\sqrt{17}

In the triangle QNP, the sides can be calculate as following:

  • Q(-4;4); N(-3;0)

             => QN = \sqrt{[-3-(-4)]^{2} + (0-4)^{2}  } = \sqrt{1^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • Q (-4;4); P(-7;1)

   => QP = \sqrt{[-7-(-4)]^{2} + (1-4)^{2}  } = \sqrt{(-3)^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • N(-3;0); P(-7;1)

             =>  NP = \sqrt{[-7-(-3)]^{2} + (1-0)^{2}  } = \sqrt{(-4)^{2}+1^{2}  } = \sqrt{16+1}=\sqrt{17}

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

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jolli1 [7]
Given that AB = 16, BC = 5, and CD = 3, which is the length of secant DE?It might be useful to see ...
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3 years ago
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