Answer:
Step-by-step explanation:
The same space of this experiment is the possible outcomes of selecting two out of the three breakfast. let the sample space = B
the sample space = {(cereal and egg), (cereal and fruit), (fruit and egg), (fruit and cereal), (egg and fruit), (egg and cereal)}
b) A = {(cereal and egg), (cereal and fruit), (egg and cereal), (fruit and cereal)}
A ⊆ B =n(A) ≤ n(B) (4≤6) = {(cereal and egg), (cereal and fruit), (egg and cereal), (fruit and cereal)} ⊆{(cereal and egg), (cereal and fruit), (fruit and egg), (fruit and cereal), (egg and fruit), (egg and cereal)} where a subset means all the element of A can be found in B.
Answer:
22/35
Step-by-step explanation:
first get a common denominator in order to add. The common denominator is 35.
the new fractions should be 7/35 + 15/35
add the top and you get 22/35
Answer:
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x^6 + 10ax^3 + 2ax^3 + 20a^2
(x^3 + 10a)(x^3 + 2a)
answer: (x^3 + 10a)(x^3 + 2a)
Hope it helps :)
Let x = Edna's age
then it follows that (x + 1) is Ellie's age and (x + 2) is Elsa's age
We can now write and equation for the sum of their ages equal to 108:
x + (x + 1) + (x +2) = 108 simplify the left side
3x + 3 = 108 subtract 3 from both sides
3x = 105 divide both sides by 3
x = 35
Edna is 35, Ellie is 36, and Elsa is 37