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3 years ago

Find the difference and enter your answer in the space provided. 1 - 14 = ?

Mathematics

1 answer:

Vinil7 [7]3 years ago

6 0

Answer:

-13

Step-by-step explanation:

1 - 14 = -13

Have a great night! :)

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for the function rule y= -2x -3, provide the x-y coordinates of the y-intercept and the x-intercept. show your work

Levart [38]

   y = -2x - 3

-- The y-intercept is the point where the graph crosses
the y-axis. But x=0 everywhere on the y-axis, so

   y = -2(0) - 3

   y = - 3 .

-- The x-intercept is the point where the graph crosses
the x-axis. But y=0 everywhere on the x-axis, so

   0 = -2x - 3

Add 2x to each side:    2x =   -3

Divide each side by 2: x =      -3/2 .

4 0

4 years ago

Read 2 more answers

Help with a b and c

djyliett [7]

5/6 x 2/2 = 10/12
1/4 x 3/3 = 3/12
2/3 x 4/4 = 8/12

5/6 + 1/4 = 13/12 (over 1 yard)
1/4 + 2/3 = 11/12 (slightly less than 1 yard)
5/6 + 2/3 = 18/12 (too much)

Here is the answer for a:
a) 5/6 and 1/4

5 0

4 years ago

A mirror should be centered on a wall. The mirror is 36 inches wide and the wall is 18 feet wide. Which equation helps determine

Lera25 [3.4K]

Linear equation is the equation in which the highest power of the unknown variable is always 1.The equation which helps determine the distance x on each side of the mirror is ,

$x+3+x=18$ .

<h3>Given information-</h3>

The length of the mirror is 36 inches.

The length of the wall is 18 feet.

The linear equation has to find out for the distance <em>x.</em>

<em />

<h3>Linear equation-</h3>

Linear equation is the equation in which the highest power of the unknown variable is always 1.

As one feet is equal to the 12 inches. Thus the length $l$ of the mirror in the feet is,

$l=\dfrac{36}{12}$

$l=3$

The mirror is 3 feet wide.

The distance on each side of the mirror is <em>x. </em>This distance is equal at both side as the mirror is centered. The distance on each side of the mirror is,

$=x+x$ .

Now the the wall is 18 feet wide which is equal to the distance each side of the mirror and the distance of the mirror. As the mirror is 3 feet wide. Thus the equation which determine the distance x on each side of the mirror can be given as,

$x+3+x=18$

Hence the equation which helps determine the distance x on each side of the mirror is ,

$x+3+x=18$ .

Learn more about the linear equation here;

brainly.com/question/2263981

7 0

3 years ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

3 years ago

J(x)=-8x+48<br><br> Find and interpret the meaning of j(5)

Grace [21]

Step-by-step explanation:

J(x)=-8x+48

J(5)=-8×5+48

J(5)=-40+48

J(5)=8

8 0

3 years ago