As it is shown in the figure, the length of the square's side s is also the length of the circle's diameter d:
s = d = 28 in.
• Computing the area of the square:
A₁ = s²
A₁ = 28²
A₁ = 28 × 28
A₁ = 784 in² ✔
• Computing the area of the circle:
A₂ = π × r²
A₂ = π × (d/2)²
A₂ = π × (28/2)²
A₂ = π × 14²
A₂ ≈ 3.14 × 14 × 14
A₂ ≈ 615.44 in² ✔
—————
• The area of the shaded portion is equal to the difference between the area of the square and the area of circle:
A = A₁ – A₂
A ≈ 784 – 615.44
A ≈ 168.56 in² <——— this is the answer (1st option).
I hope this helps. =)
The y-intercept (or line intercept) is 1, and the slope is 3
Answer:
The correct answer is:
Step-by-step explanation:
Given that:
![h(x) = f\circ g(x)= \sqrt[3]{x+3}](https://tex.z-dn.net/?f=h%28x%29%20%3D%20f%5Ccirc%20g%28x%29%3D%20%5Csqrt%5B3%5D%7Bx%2B3%7D)
![f(x) = \sqrt[3]{x+2}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx%2B2%7D)
To find:
Solution:
Let 
We have
![f\circ g(x)= \sqrt[3]{x+3}\\OR\\f( g(x))= \sqrt[3]{x+3}](https://tex.z-dn.net/?f=f%5Ccirc%20g%28x%29%3D%20%5Csqrt%5B3%5D%7Bx%2B3%7D%5C%5COR%5C%5Cf%28%20g%28x%29%29%3D%20%5Csqrt%5B3%5D%7Bx%2B3%7D)
...... (1)
Now, we have let:
Putting x = in f(x), we get
![f(x) = \sqrt[3]{x+2}\\\Rightarrow f(m) = \sqrt[3]{m+2}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx%2B2%7D%5C%5C%5CRightarrow%20f%28m%29%20%3D%20%5Csqrt%5B3%5D%7Bm%2B2%7D)
....... (2)
Comparing equation (1) and (2):
![\sqrt[3]{x+3} =\sqrt[3]{m+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B3%7D%20%3D%5Csqrt%5B3%5D%7Bm%2B2%7D)
Taking cubes both sides:
Hence,
The <em>correct answer </em>is:
Answer:
Step-by-step explanation:
I hope this helps
Answer:
9/20 for the first question 4/9 for the second question
Step-by-step explanation:
1)0.45= 45/100=9/20
2) 44444444444÷11111111111
_____________________
99999999999 ÷11111111111 =4/9
Hope this helps, have a good day. c;
