You randomly select one card from a 52-card deckFind the probability of selecting the eight of spades or the seven of hearts

Mathematics

2 answers:

Oksana_A [137]3 years ago

6 0

A pack of 52 card deck.
The 52 cards contains 13 spades and 13 hearts.

→ Probablity of getting the 8 spades = 1/52

→ Probablity of getting the 7 hearts = 1/52

Both are mutually exclusive event's.

So,

⇒ Probablity of getting 7 hearts or 8 spades = Probablity of getting the 7 hearts + Probablity of getting the 8 spades

⇒ Probablity of getting 7 hearts or 8 spades = 1/52 + 1/52

⇒ Probablity of getting 7 hearts or 8 spades = 2/52

⇒ Probablity of getting 7 hearts or 8 spades = 1/26

dangina [55]3 years ago

5 0

Answer:

2/52

Step-by-step explanation:

Because a normal deck of cards only has one eight of spades and only one of seven of heart. So that means the probability would be 2/52. Hope you get it!

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A: What are the solutions to the quadratic equation x2+9=0? B: What is the factored form of the quadratic expression x2+9? Selec

Paraphin [41]

Answer:

A. The solutions are $x=3i,\:x=-3i$ .

B. The factored form of the quadratic expression $x^2+9=(x-3i)(x+3i)$

Step-by-step explanation:

A. To find the solutions to the quadratic equation $x^2+9=0$ you must:

$\mathrm{Subtract\:}9\mathrm{\:from\:both\:sides}\\\\x^2+9-9=0-9\\\\\mathrm{Simplify}\\\\x^2=-9\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{-9},\:x=-\sqrt{-9}$