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3 years ago

You randomly select one card from a 52-card deckFind the probability of selecting the eight of spades or the seven of hearts

Mathematics

2 answers:

Oksana_A [137]3 years ago

6 0

A pack of 52 card deck.
The 52 cards contains 13 spades and 13 hearts.

→ Probablity of getting the 8 spades = 1/52

→ Probablity of getting the 7 hearts = 1/52

Both are mutually exclusive event's.

So,

⇒ Probablity of getting 7 hearts or 8 spades = Probablity of getting the 7 hearts + Probablity of getting the 8 spades

⇒ Probablity of getting 7 hearts or 8 spades = 1/52 + 1/52

⇒ Probablity of getting 7 hearts or 8 spades = 2/52

⇒ Probablity of getting 7 hearts or 8 spades = 1/26

dangina [55]3 years ago

5 0

Answer:

2/52

Step-by-step explanation:

Because a normal deck of cards only has one eight of spades and only one of seven of heart. So that means the probability would be 2/52. Hope you get it!

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Which of the following is another name for a proof by contradiction?

andrew-mc [135]

Answer:

C. Indirect Proof

Step-by-step explanation:

There are two methods of indirect proof: proof of the contrapositive and proof by contradiction.

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3 years ago

The sanctuary currently has 125 exotic fish. The average amount of the tank allotted for each fish is represented by the binomia

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3 years ago

Given sec theta=-4/3 and 90°

hoa [83]

Answer:

Option A.

Step-by-step explanation:

It is given secθ = - $\frac{4}{3}$

then cosθ = - $\frac{3}{4}$

Now we know the identity

sinθ = $\sqrt{1-cos^{2}\theta }$

= $\sqrt{1-(-\frac{3}{4} )^{2}}$

= $\frac{\sqrt{7} }{4}$

Now sin2θ = 2sinθcosθ

Now we put the values of cosine and sine in the formula

sin2θ = 2×(- $\frac{3}{4}$ )( $\frac{\sqrt{7}}{4}$ )

= - $\frac{3\sqrt{7}}{8}$

Therefore, option A. is the answer.

3 0

3 years ago

Clarke paid $5 each for three pairs of earrings. The tax rate was 7%. What is the amount Clarke paid?

Mrac [35]

Answer:

5 x 3 = 15

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she paid $25.50

7 0

2 years ago

Read 2 more answers

The function in Exercise represents the rate of flow of money in dollars per year. Assume a 10-year period at 8% compounded cont

Kryger [21]

Answer:

a) $P= $56,972.5$

b) $A=$1,26,792.3$

Step-by-step explanation:

Given Data:

Interest rate= $r= 0.08$ per year

No. of years= $t=10$

Rate of continuous money flow is given by the function

$f(t)=2000$

a) to find the present value of money

$P=\int\limits^n_0 {f(t)e^{-rt} } \, dt$

Put f(t)=2000 and n=10 years and r=0.08

$P=\int\limits^n_0 {2000e^{-0.08t} } \, dt$

Now integrate

$P= {2000(\frac{e^{-0.08t}}{-0.08} )$

$P= -\frac{2000}{0.08} (e^{-0.08*10}-e^{-0.08*0})$

$P= -\frac{2000}{0.08} (e^{-0.8}-e^{0})$

$P= -\frac{2000}{0.08} (0.4493-2.7282)$

$P= -\frac{2000}{0.08} (-2.2789)$

$P= -25000(-2.2789)$

$P= $56972.5$

(b) to find the accumulated amount of money at t=10

$A=P(e^{rt} )$

Where P is the present worth already calculated in part a

$A=56972.5(e^{0.08*10} )$

$A=56972.5(e^{0.8} )$

$A=56972.5(2.2255 )$

$A=$1,26,792.3$

5 0

3 years ago