You randomly select one card from a 52-card deckFind the probability of selecting the eight of spades or the seven of hearts

Mathematics

2 answers:

Oksana_A [137]3 years ago

6 0

A pack of 52 card deck.
The 52 cards contains 13 spades and 13 hearts.

→ Probablity of getting the 8 spades = 1/52

→ Probablity of getting the 7 hearts = 1/52

Both are mutually exclusive event's.

So,

⇒ Probablity of getting 7 hearts or 8 spades = Probablity of getting the 7 hearts + Probablity of getting the 8 spades

⇒ Probablity of getting 7 hearts or 8 spades = 1/52 + 1/52

⇒ Probablity of getting 7 hearts or 8 spades = 2/52

⇒ Probablity of getting 7 hearts or 8 spades = 1/26

dangina [55]3 years ago

5 0

Answer:

2/52

Step-by-step explanation:

Because a normal deck of cards only has one eight of spades and only one of seven of heart. So that means the probability would be 2/52. Hope you get it!

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Please help fast, thanks !

Maslowich

Answer:

a) 0.8

b) 0.3

c) 0.9

d) 0.95

Step-by-step explanation:

A probability always adds up to 1. It is between the scale of 0 (never likely) to 1 (very likely).

So:

1 - 0.2 = 0.8

1 - 0.7 = 0.3

1 - 0.1 = 0.9

1 - 0.05 = 0.95

Hope this helped!

8 0

2 years ago

Rationalize the denominator.

AlekseyPX

Hello and Good Morning/Afternoon!

Let's take this problem step-by-step:

What the problem asks for:

⇒ to rationalize the denominator

⇒ rationalize means that you multiply the numerator and

demonimator by the denominator

Let's put that into action:

$\frac{\sqrt{a +1}-2 }{\sqrt{a+1}+2 } * \frac{\sqrt{a +1}+2 }{\sqrt{a+1}+2 }\\=\frac{a +1-4 }{a+1+4\sqrt{a+1}+4 } \\=\frac{a-3}{a+4\sqrt{a+1}+5 }$ <== Answer