Type the numerical answer ONLY. (no spaces)
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Answer:
Step-by-step explanation:
This is a test of 2 population proportions. Let m and w be the subscript for men and women players. The population proportions would be pm and pw
Pm - Pw = difference in the proportion of male and female players.
The null hypothesis is
H0 : pm = pw
pm - pw = 0
The alternative hypothesis is
Ha : pm ≠ pw
pm - pw ≠ 0
it is a two-tailed test
Sample proportion = x/n
Where
x represents number of success
n represents number of samples
For men,
xm = 1027
nm = 2441
Pm = 1027/2441 = 0.42
For women,
xw = 509
nw = 1273
Pw = 509/1273 = 0.4
The pooled proportion, pc is
pc = (xm + xw)/(nm + nw)
pc = (1027 + 509)/(2441 + 1273) = 0.41
1 - pc = 1 - 0.41 = 0.59
z = (Pm - Pw)/√pc(1 - pc)(1/nm + 1/nw)
z = (0.42 - 0.4)/√(0.41)(0.59)(1/2441 + 1/1273) = 0.02/√0.0002891223
z = 1.18
Since it is a 2 tailed test, we would find the p value by doubling the area to the right of the z score to include the area to left.
Area to the right from the normal distribution table is
1 - 0.881 = 0.119
P value = 0.119 × 2 = 0.238
Since 0.05 < 0.238, we would accept the null hypothesis
Therefore, there is no sufficient evidence to conclude that that men and women have unequal success in challenging calls.
You're probably supposed to find the value of p and not x, which is impossible to do.
Expanding gives
We're told that
which we can use to solve for p: