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aniked [119]
3 years ago
9

What is the perimeter of a triangle with the side lengths 4 cm, 6 cm, and (3y-2) cm?

Mathematics
1 answer:
jek_recluse [69]3 years ago
7 0

Answer:

Step-by-step explanation:

P = 4 + 6 + (3y - 2)      Remove the brackets

P = 10 + 3y - 2            Combine

P = 8 + 3y

Note 3y must be less than 8. That's because 2 sides of any triangle must be larger than the 3rd side or else you don't have a triangle.

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Find the equation of the line that is perpendicular to the line
ddd [48]

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Step-by-step explanation:

Hi there!

<u>What we need to know:</u>

  • Linear equations are typically organized in slope-intercept form: y=mx+b where m is the slope and b is the y-intercept (the value of y when x is 0)
  • Perpendicular lines always have slopes that are negative reciprocals (ex. 3 and -1/3, 5/6 and -6/5, etc.)

<u>1) Determine the slope (m)</u>

y=x-9

Rewrite the equation

y=1x-9

Now, we can identify clearly that the slope of the line is 1. The negative reciprocal of 1 is -1, so therefore, the slope of a perpendicular line would be -1. Plug this into y=mx+b:

y=-1x+b\\y=-x+b

<u />

<u>2) Determine the y-intercept (b)</u>

y=-x+b

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Add 7 to both sides to isolate b

9+7=-7+b+7\\16=b

Therefore, the y-intercept is 16. Plug this back into y=-x+b:

y=-x+16

I hope this helps!

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