23 multiplied by 18 is 414
Answer:
Step-by-step explanation:
To test the hypothesis is the mean SAT score is less than 1520 at 5% significance level
The nul hypothesis is
The alternative hypothesis is
The test statistic is
The t - test statistics is -1.603
The t - critical value is,
The small size is small and left tail test.
Look in the column headed and the row headed in the t - distribution table by using degree of freedom is,
d.f = n - 1
= 20 - 1
= 19
The t - critical value is -1.729
The conclusion is that the t value corresponds to sample statistics is not fall in the critical region, so the null hypothesis is not rejected at 5% level of significance.
there is insignificance evidence ti indicate that the mean SAT score is less than 1520. The result is not statistically significant
Y would be 3 then.
Beacuse the equation is y=Mx+c
So if you substitute the values it will be
y=2(0)+3
Y=0+3
Y=3