Our quadratic polynomial function is:
f(x) = 4x^2 + 2x + 5
our linear binomial form is:
x - a = -2
hence:
a = x + 2
and so we have:
f(x) = 4x^2 + 2x + 5
f(a) = 4(x + 2)^2 + 2<span>(x + 2)</span> + 5
= 4(x^2 + 4x + 4) + 2x + 4 + 5
f(a) = 4x^2 + 18x + 25
C because the square root of 64 is 8
Answer:
The equation of plane is x-y+z=12.
Step-by-step explanation:
It is given that the plane passing through the point (0,0,6) perpendicular to x=1-t y=2+t z=4-2t.
The given line is perpendicular to required plane, so coefficients of t represents the normal vector.
Normal vector is

If a plane passes through
and having normal vector
, then the equation of plane is




Multiply both sides by -1.

Therefore, the equation of plane is x-y+z=12.
It’s A
I have done that befor
K/2+9=30 1. Start by getting rid of the number farthest from K
-9 -9 2. The nines cancel out, 30-9=21
K/2 = 21 3. Next, get the 2 away from K
/-2 /-2 4. The 2 cancel out when divided, 21 divided by -2= -10.5
K = -10.5
K=-10.5