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mafiozo [28]
3 years ago
6

346772.99378 x 222222666886=

Mathematics
1 answer:
nordsb [41]3 years ago
6 0

Answer:

7.706081948 lowecase10uppercase16

Step-by-step explanation:

I hope it helps u.

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alukav5142 [94]

Answer:

The distance covered is 113.75 m

Step-by-step explanation:

As per the question:

The initial velocity of the train, v = 20 m/s

The final velocity of the train, v' = 6 m/s

Uniform deceleration, a = 1.6m/s^{2}

Or uniform acceleration, a = - 1.6m/s^{2}

<em>Here, the body decelerates, i.e., slows down at a uniform rate thus we take acceleration with negative sign.</em>

Now, to find the distance covered, s:

Using the eqn of Kinemetics:

v'^{2} = v^{2} + 2as

6^{2} = 20^{2} + 2(- 1.6)s

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s = \frac{- 364}{- 3.6} = 113.75\ m

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3 years ago
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