Okay. fist off don't think of them as 5 units each, but 1. so if you were to put it on graphing paper and box squares each time. you would be able to get 8 in for both sides to make a square. Area then would be 1600ft squared because 8 ×5 is 40 and 40×40 is 1600. then you calculate how many squares you used. 8×8=64. and 80-64=16 so 16 pieces are left over. then 9×9 (increasing the square) is 81. so 17 pieces to increase it.
One box of candy costs $1.50. A movie rental costs $2.
Answer:
21.70
Step-by-step explanation:
First find the discount
31 * 30%
31 *.30
9.3
Subtract from the original amount
31 - 9.3
21.70
Answer:
The minimum sample size is n = 75 so that the desired margin of error is 5 or less.
Step-by-step explanation:
We are given the following in the question:
Population variance = 484
Standard deviation =

Confidence level = 0.95
Significance level = 0.05
Margin of error = 5
Formula:
Margin of error =


Putting values, we get

Thus, the minimum sample size is n = 75 so that the desired margin of error is 5 or less.