All categories

2 years ago

Consider two bases B = {b1, b2, b3} and C = {c1, c2, c3} for a vector space V such that

Mathematics

1 answer:

Helen [10]2 years ago

3 0

I’m a failure if you can just say “yes you are” in the comments

You might be interested in

Pls help me with this, i’ll give brainly

Nataly_w [17]

Answer:

shirts = 15 when pants = 6

Step-by-step explanation:

Try two others that are given

shirts / pants = 10 / 4 = 2.5

shirts / pants = 30/12 = 2.5

So shirts/pants = 2.5 = x/6

2.5 = x / 6 Multiply by 6

2.5 * 6 = x

x = 15

8 0

2 years ago

If sin(x) = 5/13, and x is in quadrant 1, then tan(x/2) equals what?

Rufina [12.5K]

$x$ is in quadrant I, so $0$ , which means $0$ , so $\dfrac x2$ belongs to the same quadrant.

Now,

$\tan^2\dfrac x2=\dfrac{\sin^2\frac x2}{\cos^2\frac x2}=\dfrac{\frac{1-\cos x}2}{\frac{1+\cos x}2}=\dfrac{1-\cos x}{1+\cos x}$

Since $\sin x=\dfrac5{13}$ , it follows that

$\cos^2x=1-\sin^2x\implies \cos x=\pm\sqrt{1-\left(\dfrac5{13}\right)^2}=\pm\dfrac{12}{13}$

Since $x$ belongs to the first quadrant, you take the positive root ( $\cos x>0$ for $x$ in quadrant I). Then

$\tan\dfrac x2=\pm\sqrt{\dfrac{1-\frac{12}{13}}{1+\frac{12}{13}}}$

$\tan x$ is also positive for $x$ in quadrant I, so you take the positive root again. You're left with

$\tan\dfrac x2=\dfrac15$

4 0

3 years ago

Consider the function below.

vovangra [49]

An inverse function reverses (x, f(x)) to make it (f(x), x).

The 1st selection does that.

5 0

3 years ago

Read 2 more answers

Give brainliest what is the meaning of mode in mathmatics

Oksana_A [137]

The number which appears most often in a set of numbers. Example: in {6, 3, 3, 6, 3, 5, 9, 3} the Mode<span> is 3 (it occurs most often). Does this help???</span>

5 0

3 years ago

Read 2 more answers

This app man its soo annoying why is it covering up the answers of the questions , like blaring it .

matrenka [14]

Answer:

fr it does that to me lol and then i have to press on the ad fr

Step-by-step explanation:

7 0

2 years ago