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Tju [1.3M]
2 years ago
13

The width of an extra large rectangle poster is 8 inches more than half its length.The area of this poster is 306 square inches

Mathematics
1 answer:
maria [59]2 years ago
8 0

Answer:

a² + 16a - 612 = 0

Step-by-step explanation:

Here is the complete question :

The width of an extra large rectangle poster is 8 inches more than half its length. The area of this poster is 306 square inches

Write an equation in one variable that could be used to find the number of inches in the dimensions of this poster.

Area of a rectangle = length x width

Let length = a

width = 8 + 1/2a

Area =  (8 + 1/2a) x a

306 =  (8 + 1/2a) x a

multiply both sides of the equation by 2

612 = 16a + a²

a² + 16a - 612 = 0

the dimensions of the poster can be determined using quadratic formula

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Substitute the values:

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A = 2 (25 + 15 + 15)

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Read 2 more answers
Please help me answer this for a test im having trouble
Dimas [21]

Answer:

x + 1

y = 9

Step-by-step explanation:

In order to solve this question we need to represent "y "in terms of "x" in the first equation, and the plug in the "y" value in the first equation into the second one. Luckily for us in the first equation it already shows what "y" is equal to in terms of "x" (based on the first equation y = -x + 10). Now we just need to plug in the value that we got instead of "y" in the second equation, and so we get....

y = 7x + 2

(plug in the y value and get the following ….)

-x + 10 = 7x + 2

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3 years ago
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