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Tju [1.3M]
3 years ago
13

The width of an extra large rectangle poster is 8 inches more than half its length.The area of this poster is 306 square inches

Mathematics
1 answer:
maria [59]3 years ago
8 0

Answer:

a² + 16a - 612 = 0

Step-by-step explanation:

Here is the complete question :

The width of an extra large rectangle poster is 8 inches more than half its length. The area of this poster is 306 square inches

Write an equation in one variable that could be used to find the number of inches in the dimensions of this poster.

Area of a rectangle = length x width

Let length = a

width = 8 + 1/2a

Area =  (8 + 1/2a) x a

306 =  (8 + 1/2a) x a

multiply both sides of the equation by 2

612 = 16a + a²

a² + 16a - 612 = 0

the dimensions of the poster can be determined using quadratic formula

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Two forces of 17 and 42 pounds act horizontally on an object.

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F1 = 17 pounds

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As the magnitude of the force represents the sum of all the forces

The direction is the same

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The Direction angles : 0

As they have the same direction so angle will be 0.

The forces have a magnitude of 59 pounds, and their direction angles are zero.

To learn more about the Magnitude of forces and Direction angles of forces, refer to:

brainly.com/question/14584426

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