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telo118 [61]
2 years ago
13

Consider polynomial function f(x)=(x-1)^2(x+3)^3 (+1) Use the equation to complete each statement about this function.

Mathematics
1 answer:
Ber [7]2 years ago
3 0

Answer:

I got you my man

Step-by-step explanation:

Blank 1: 2

Blank 2: 3

Blank 3: 1 only

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Please help
Korvikt [17]

Answer:

b. c(p) = 0.42p

Step-by-step explanation:

you are multiplying the cost (0.42) by the pounds (p)

7 0
3 years ago
Read 2 more answers
Please help!!!!!!!!!!!!!!!!
aksik [14]

Step-by-step explanation:

< PQS is exterior angle of the triangle

So,

2X = X + 58

X=58

m < P = 58

m <P QR = 180 - ( 58 + 58 ) =, 64

m < P QS = 116

6 0
3 years ago
Find the value of c that makes t^2 - 22t+ c a perfect square trinomial.
allochka39001 [22]

The expression is a perfect square trinomial if and only if c = 121.

<h3>How to get the value of c?</h3>

A perfect square trinomial is written as:

(a + b)^2 = a^2 + b^2 + 2ab

In this case, we have:

t^2 - 22t + c

We can rewrite this as:

t^2 - 2*11*t + c

Then we have:

a = t

b = -11

And we will have that:

c = b^2 = (-11)^2 = 121

Then we have:

t^2 - 2*11*t + 121

Which is a perfect square trinomial:

(t - 11)^2 = t^2 - 22t + 121

Learn more about perfect squares:

brainly.com/question/1538726

#SPJ1

8 0
1 year ago
A store sells boxes of tissue that have 6 tissues in each box. The boxes are arranged 3 across and 4 deep on each shelf. How man
natka813 [3]

Number of boxes = 3 across x 4 deep = 12 total boxes.

Each box has 6 tissues.

Total tissues = 6 per box x 12 boxes = 72 tissues.

4 0
3 years ago
A coin is tossed 8 times. What is the probability of getting all heads? Express your answer as a simplified fraction or a decima
kumpel [21]

Answer:

The probability of getting all heads is \frac{1}{256}.

Step-by-step explanation:

For each time the coin is tossed, there are only two possible outcomes. Either it is heads, or it is not. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

A coin is tossed 8 times. This means that n = 8

In each coin toss, heads or tails are equally as likely. So p = \frac{1}{2}

What is the probability of getting all heads?

This is P(X = 8)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

[tex]P(X = 8) = C_{8,8}*(\frac{1}{2})^{8}*(1 - \frac{1}{2})^{0} = \frac{1}{256}

The probability of getting all heads is \frac{1}{256}.

7 0
3 years ago
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