Question

Mathematics please help...​

Answer 1

Answer:

the answer is B

Step-by-step explanation:

area of the minor arc is teter all over 360 times 2 pie r square.

that is

$\frac{?}{360} \times 2\pi {r}^{2}$

= but because the question said for length AB, youvhave to use only one radius.

$\frac{160}{360} \times 2 \times \pi \times 9$

You the use 40 to cancel 160 and 360 to get 4 all over 9 times 2 pie times 9.

$\frac{4}{9} \times 2 \times \pi \times 9$

You then cancel 9 with 9 to get 4 times 2 times pie

$4 \times 2 \times \pi$

this is equal to

$8\pi$