1,260 possible arrangements of "balloon" using 7!/[2!*2}
We are asked to solve for the width "x" in the given problem. To visualize the problem, see attached drawing.
We have the area of the swimming pool such as:
Area SP = l x w
Area SP = 10 * 16
Area SP = 160 feet2
Area of the swimming pool plus the sidewalk with uniform width:
Area SP + SW = (10 + x) * (16 + x)
160 + 155 = 160 + 10x + 16x + x2
160 -160 + 155 = 26x + x2
155 = 26 x + x2
x2 + 26x -155= 0
Solving for x, we need to use quadratic formula and the answer is 5 feet.
The value of x is
<span>
5 feet. </span>
Answer:
2,75in
4,25in
33in²
Step-by-step explanation:
shorter base is 2,75in
larger base is 4,25in
S=11+10,5+9+2,5=33in²
Answer:
150 feet by 300 feet.
Step-by-step explanation:
The fence is to enclose a rectangular area of 45,000 ft squared.
If the dimensions of the rectangle are x and y
Area of a rectangle = xy
- xy=45000

Perimeter of the Rectangle =2x+2y
Fencing material costs $ 3 per foot for the two sides facing north and south and $6 per foot for the other two sides.
- Cost of Fencing, C=$(6*2x+3*2y)=$(12x+6y)
Substitute
into the Cost to get C(y)
C=12x+6y

The value at which the cost is least expensive is at the minimum point of C(y), when the derivative is zero.


Recall,

Since x=150, y=300
The dimensions that will be least expensive to build is 150 feet by 300 feet.