Answer:
Option B. 1.8 seconds
Step-by-step explanation:
h=-16t^2+56t+1
This is a quadratic equation, and its graph is a parabola
h=at^2+bt+c; a=-16, b=56, c=1
Like a=-16<0 the parabola opens downward, and it has a maximum value (height) at the vertex, at the abscissa:
Replacing the known values:
Approximately 1.8 seconds.
Answer: It takes approximately 1.8 seconds the airplane to reach its maximum height.
Given:
The temperature of the first 6 days in march is:
23F, 58F, 62F, 64F, 64F, 65F
23 F is removed from the data set.
To find:
How much greater is the range of the original 6 temperatures than the range of the 5 temperatures.
Solution:
Range of a data set is:
Range = Maximum value - Minimum value
The given data set is:
23 F, 58 F, 62 F, 64 F, 64 F, 65 F
The range of given data set is:
Range = 65 - 23
= 42
If the temperature 23 F is removed from the data set, then the new data set is:
58 F, 62 F, 64 F, 64 F, 65 F
The range of this new data set is:
Range = 65 - 58
= 7
Now, the difference between original range and new range is:
The original range is 35 more than the new range. Therefore, the correct option is a.