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den301095 [7]
3 years ago
6

Which of the following numbers can be expressed as repeating decimals?

Mathematics
2 answers:
Ivahew [28]3 years ago
7 0

C

Because i know so yea. hola soy dora.

uranmaximum [27]3 years ago
7 0

Answer:

C

Step-by-step explanation:

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A ball is kicked from ground level with a velocity of 20 m/s at 30 degrees above the horizontal. Determine the horizontal displa
olga55 [171]

Answer:the horizontal displacement is 34.64 meters

The maximum height is 15 meters

Step-by-step explanation:

As the ball moves from the ground at 30 degrees, it travels through a parabolic path. It can therefore be likened to a projectile. The horizontal displacement to where it lands is the range. The formula for determining range,R is

R = U^2Sin2#)/g

Where

U represents the initial velocity of the ball

g is acceleration due to gravity

# represents the angle above the horizontal.

From the information given

# = 30 degrees

U = 20 m/s

g = 10m/s^2

R = 20^2Sin2×30)/10 = (400Sin60)/20 = (400×0.8660)/10

= 34.64 meters

To determine the maximum height of the ball, H,

H = (U^2Sin^2#)/2g

H = (20^2 × Sin^2 30)/2×10

H = (400 × 0.866^2)/20 = 15 meters

4 0
4 years ago
A twelve pack of soda is on sale for $2.64. What is<br> the cost for one
vlabodo [156]

Answer:$1.32

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Orange M&amp;M’s: The M&amp;M’s web site says that 20% of milk chocolate M&amp;M’s are orange. Let’s assume this is true and set
SOVA2 [1]

Answer:

The correct option is (A).

Step-by-step explanation:

Let <em>X</em> = number of orange  milk chocolate M&M’s.

The proportion of orange milk chocolate M&M’s is, <em>p</em> = 0.20.

The number of candies in a small bag of milk chocolate M&M’s is, <em>n</em> = 55.

The event of an milk chocolate M&M being orange is independent of the other candies.

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 55 and <em>p</em> = 0.20.

The expected value of a Binomial random variable is:

E(X)=np

Compute the expected number of orange  milk chocolate M&M’s in a bag of 55 candies as follows:

E(X)=np

         =55\times 0.20\\=11

It is provided that in a randomly selected bag of milk chocolate M&M's there were 14 orange ones, i.e. the proportion of orange milk chocolate M&M's in a random bag was 25.5%.

This proportion is not surprising.

This is because the average number of orange milk chocolate M&M’s in a bag of 55 candies is expected to be 11. So, if a bag has 14 orange milk chocolate M&M’s it is not unusual at all.

All unusual events have a very low probability, i.e. less than 0.05.

Compute the probability of P (X ≥ 14) as follows:

P(X\geq 14)=\sum\limits^{55}_{x=14}{{55\choose x}0.20^{x}(1-0.20)^{55-x}}

                 =0.1968

The probability of having 14 or more orange candies in a bag of milk chocolate M&M’s is 0.1968.

This probability is quite larger than 0.05.

Thus, the correct option is (A).

4 0
3 years ago
How could I get rid of the 3 shown in equation 1?
Tems11 [23]

Answer:

Step-by-step explanation:

3 log 2+log (x-4)=log 2³+log (x-4)=log 8+log (x-4)=log 8(x-4)

8 0
3 years ago
3. Write the numbers given below in scientific notation.<br>(a) 3000000000 ms<br><br>​
k0ka [10]

Step-by-step explanation:

3×10^10 is the scientific notation of 30000000000

8 0
3 years ago
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