On a given line, (on one side) there are a total of 180°
if one line in Problem #3 is bisected by a line, with one half X and the other 120°,
do 180° (the total) minus 120° which=60°
now the hard part, that line that bisected the first line is bisecting a line that is parallel to your second line, the one with <5 and <6
this means that the big angle formed in the first one with 120° is the same angle as in the second line, leaving <5 as 120°
which means <6 is 60°, like in the top part of the problem. You're basically flipping the top line upside down, I hope it helps.
In the given triangle, the verteces are A(-4, 1), B(-6, 5), C(-1, 2).
A refrection across the x-axis will result in A'(-4, -1), B'(-6, -5), C'(-1, -2)
A translation of 1 unit to the right will result in A"(-3, -1), B"(-5, -5), C"(0, -2)
A translation of 1 unit down will result in A"'(-3, -2), B"'(-5, -6), C"'(0, -3) which corresponds to points DEF.
Therefore, the series of transformation required to transform ABC to DEF are <span>a reflection across the x-axis followed by a translation of 1 unit right and 1 unit down.</span>
X=5 is the answer for this problem
Answer:
Step-by-step explanation:
The absolute value function prevents the expression from being a polynomial. The degree of 3 in y^3 is an odd number so that polynomial function will not be even.
B, because 40 and 40 make 80 and 180-80=100<span />
