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givi [52]
3 years ago
15

I do not know how to do this but I need a answer cuz u don’t know it

Mathematics
1 answer:
svetlana [45]3 years ago
4 0
                 16.2
             ________
       25  | 405.0
            -  25
            --------
               155
             - 150
             ---------
                    50
                 -  50
                 -------
                       0
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Identify the maximum or minimum value and the domain and range of the graph of the function y = 2(x – 3)2 – 4.
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We are given the equation y = 2(x – 3)^2 – 4 and is asked for the domain and range of the following function. In this case, there is no radical sign so the domain includes all real numbers. The range has a minimum value of -4 since the squaring makes the value on the first term positive. Hence the answer is A. 
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Fifty eight students were surveyed about how frequently they text during lunch. The results are summarized below. Which statemen
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Answer:The median number is 9 , Q3 is 11, data is skewed left, lowest 25%

Step-by-step explanation:

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3 years ago
Help me with these questions
natulia [17]
Number 5a.  is 26.78 and 5b. is 8.5
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3 years ago
2. Solve the following system of equations. y = 5 + x 2x + 2y = 30
larisa86 [58]
X = 5

since we know y= 5 + x , plug this into y in the second equation.

2x + 2 (5 + x) = 30

distribute 2 into the 5 and x

2x + 10 + 2x = 30

combine like terms

4x + 10 = 30

subtract 10 from both sides

4x = 20

divide four by both sides to isolate the variable

x = 5
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3 years ago
Read 2 more answers
Start with the basic function f(x)=2x. If you have an initial value of 1, then you end up with the following iterations. f(1)=2*
denpristay [2]
<span>f(x)=2x

f(1)=2*1=2

f^2(1)=2*2*1=4

f^3(1) =2*2*2*1=8

1. If you continue this pattern, what do you expect would happen to the numbers as the number of iterations grows?

I expect the numbers continue growing multiplying each time by 2.

Check your result by conducting at least 10 iterations.

f^4(1) = f^3(1) * f(1) = 8*2 = 16

f^(5)(1) = f^4(1) * f(1) = 16 * 2 = 32

f^6 (1) = f^5 (1) * f(1) = 32 * 2 = 64

f^7 (1) = f^6 (1) * f(1) = 64 * 2 = 128

f^8 (1) = f^7 (1) * f(1) = 128 * 2 = 256

f^9 (1) = f^8 (1) * f(1) = 256 * 2 = 512

f^10 (1) = f^9 (1) * f(1) = 512 * 2 = 1024

2. Repeat the process with an initial value of −1. What happens as the number of iterations grows?

f(-1) = 2(-1) = - 2

f^2 (-1) = f(-1) * f(-1) = - 2 * - 2 = 4

f^3 (-1) = f^2 (-1) * f(-1) = 4 * (-2) = - 8

f^4 (-1) = f^3 (-1) * f(-1) = - 8 * (-2) = 16

f^5 (-1) = f^4 (-1) * f(-1) = 16 * (-2) = - 32

As you see the magnitude of the number increases, being multiplied by 2 each time, and the sign is aleternated, negative positive negative positive ...
</span>
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4 years ago
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