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3 years ago

5x+8y=-12 3x+5y=-7 what is the solution

Mathematics

2 answers:

Burka [1]3 years ago

6 0

Answer:

$5x + 8y = - 12 - - - (a) \\ 3x + 5y = - 7 - - - (b) \\ 3\times (a) - 5 \times (b) : \\ = > 0x - y = - 1 \\ y = 1 \\ 3x + 5 = - 7 \\ 3x = - 12 \\ x = 4 \\ { \boxed{x = - 4}} \\ { \boxed{y = 1}}$

OverLord2011 [107]3 years ago

3 0

X = -4 Y = 1 are the answers ifkffjdjskvisjnencjdnsn

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Solve for x and y: 3x + 7y= 22 123 + 28y = 88

ale4655 [162]

Answer:

Step-by-step explanation:

1. Since this is a equation we know we have to get the variables to one side and the constants/rational numbers to the other. So you take 7y and you add -7y. You do that to the other side which will give you -4y=22. Since we cant have a negative variable, you flip the y to positive and flip the constant to negative leaving you 4y=-22. Then you distribute y leaving you y=-5.5

2.since we know the constants must be on 1 side of the equal sign, we subtract 123 on both sides, leaving us with 28y=-35. Distribute y and you get y=-0.8

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4 years ago

Enter a formula in cell B3 using the Vlookup function to find the meaning for thr medical abbrevation listed in cell A3. use the

NeX [460]

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3 years ago

Marty is asked to draw triangles with side lengths of 4 units and 2 units, and a non-included angle of 30°. Select all the trian

777dan777 [17]

Answer:

The drawn in the attached figure

see the explanation

Step-by-step explanation:

First case

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\B=30^o$

Applying the law of sines

Find the measure of angle A

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(A)}=\frac{2}{sin(30^o)}$

$sin(A)=1$

$A=90^o$

Find the measure of angle C

In a right triangle

we know that

$B+C=90^o$ ----> by complementary angles

$B=30^o$

therefore

$C=60^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{c}{sin(60^o)}=\frac{2}{sin(30^o)}$

$c=2\sqrt{3}\ units$

therefore

The dimensions of the triangle are

$A=90^o$

$B=30^o$

$C=60^o$

$a=4\ units\\b=2\ units\\c=2\sqrt{3}=3.46\ units$

Second case

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\A=30^o$

Applying the law of sines

Find the measure of angle B

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(30^o)}=\frac{2}{sin(B)}$

$sin(B)=0.25$

using a calculator

$B=14.48^o$

Find the measure of angle C

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

$A+B+C=180^o$

$A=30^o\\B=14.48^o$

therefore

$30^o+14.48^o+C=180^o$

$C=135.52^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{a}{sin(A)}$

substitute the given values

$\frac{c}{sin(135.52^o)}=\frac{4}{sin(30^o)}$

$c=5.61\ units$

therefore

The dimensions of the triangle are

$A=30^o$

$B=14.48^o$

$C=135.52^o$

$a=4\ units\\b=2\ units\\c=5.61\ units$

see the attached figure to better understand the problem

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3 years ago

What is a half of 104

Mumz [18]

52 is half of 104.
Is ur answer.

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4 years ago

Read 2 more answers

Math grades assignment unit test part 2 adding and subtracting rational numbers?

Katena32 [7]

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Step-by-step explanation:

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