Answer:
12 feets
Step-by-step explanation:
Let the area of the pool be Length×width
There will be 2lengths and 2widths as well so the perimeter of the pool will be the addition of all the sides of the pool i.e 2L + 2W = 96... (1)
And since the length of the pool is 3 times its width, we have
L = 3W... (2)
Substituting equation 2 into 1 to get the width 'W'
2(3W) + 2W = 96
6W + 2W = 96
8W = 96
W = 96/8
W = 12feets
The width of the pool is 12feets
A volume:
V = 3.00 in³
1 in³ = 16.39 cm³
V = 3.00 · 16.39 = 49.17 cm³
0.242 g/cm³ · 49.17 g = 11.899 g² ≈ 11.90 g
Answer: It would weigh 11.90 grams.
C=2pir
V=(4/3)pir^3
solve for V
C=31.4
31.4=2pir
divide by 2
15.7=pir
divide both sides by pi or 3.14
5=r
V=(4/3)pir^3
V=(4/3)pi5^3
V=(4/3)pi125
V=(500/3)*3.14
V=523.33333333333333333333333333333
rounded
523 cubic inchs
Answer:28inches & 84inches
First, lets write an equation that fits the data given. The string is 112 inches long. When the two pieces are cut, the first piece will be three times as long as the second piece. If we use the variable, x, to represent the second piece, we can create the following equation...
112=3x+x
Now lets solve for x.
112=4x
divide both sides by 4
28 inches=x
Now we know that the second piece is 28inches long. Since the first piece is three times as long, simply multiply 28*3 and we'll know the length of the first piece.
28*3=84 inches
28+84=112
2 for sureee
If not then sorry mate
