! et up your proportions) Eduardo counted eight seconds between seeing lightning and hearing thunder, and he knew that the light
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(as opposed to <em>x</em> approaching 2)
Since both the numerator and denominator are continuous at <em>t</em> = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:
Because these expressions are continuous at <em>t</em> = 2, we can compute the limits by evaluating the limands directly at 2:
Answer:
The age of brothers are 4 years and 2 years respectively.
Step-by-step explanation:
We are given that the ages of two brothers have a ratio of 2 to 1. When 4 years have passed, the ratio of their ages will be 8 to 6.
Let the age of the first brother be 'x years' and the age of the second brother be 'y years'.
So, according to the question;
- The first condition states that the ages of two brothers have a ratio of 2 to 1, that means;
-------------- [equation 1]
- The second condition states that when 4 years have passed, the ratio of their ages will be 8 to 6, that means;
= 2 years
Putting the value of y in equation 1 we get;
x = 2y
x = = 4 years
Hence, the age of brothers are 4 years and 2 years respectively.