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const2013 [10]
3 years ago
12

Find the surface area/volume for each

Mathematics
1 answer:
Karolina [17]3 years ago
7 0

Answer:

goodjob

Step-by-step explanation:

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Find the quanity 103% of 19
Basile [38]

Answer:

19.57

Step-by-step explanation:

100% of 19 is 19.

In order to find out what 1% of 19, move the decimal point two place to the left. 1% of 19= 0.19. To find 3% of 19, multiply .19 x 3. add 0.19 x 3 to 19, aka add 0.57 to 19 to get 19.57= 103% of 19

6 0
3 years ago
Read 2 more answers
Find r if 0=pi/6 rad sector 64m^2
kap26 [50]

Given:

Area of a sector = 64 m²

The central angle is \theta=\dfrac{\pi}{6}.

To find:

The radius or the value of r.

Solution:

Area of a sector is:

A=\dfrac{1}{2}r^2\theta

Where, r is the radius of the circle and \theta is the central angle of the sector in radian.

Putting A=64,\theta=\dfrac{\pi}{6}, we get

64=\dfrac{1}{2}r^2\times \dfrac{\pi}{6}

64=\dfrac{\pi}{12}r^2

64\times \dfrac{12}{\pi}=r^2

\dfrac{768}{\pi}=r^2

Taking square root on both sides, we get

\sqrt{\dfrac{768}{\pi}}=r

16\sqrt{\dfrac{3}{\pi}}=r

Therefore, the value of r is 16\sqrt{\dfrac{3}{\pi}} m.

6 0
3 years ago
(PLEASEEE HELP ASAP!!) The Sugar Sweet Company will choose from two companies to transport Its sugar to market. The first compan
LiRa [457]

Answer:

Q1:14 Q2:8903.5

Step-by-step explanation:

I find that using equations to solve problems makes it a lot easier.

The first company's equation would be y=5743+225.75x because 5743 is the set fee and 225.75 is for each ton of sugar. The second company would be y=7500+100.25x for the same reasons.

So we need to find a value of x that works for each company and a value of y that is the same for the cost.

Now we combine them.

Solve for x:

5743+225.75x=7500+100.25x

-5743                -5743

225.75x= 1757+100.25x

-100.25x           -100.25x

125.50x=1757

/125.5     /125.5

x=14

Therefore, for Q1, the answer is 14.

Now we solve for y by substituting x for 14.

5743+225.75(14)

5743+3160.5

8903.5

We can also check this with the other equation

7500+100.25(14)

7500+1403.5

8903.5

So therefore, the answer to Q2 would be 8903.5.

8 0
3 years ago
Please help me with this
vlada-n [284]

Step-by-step explanation:

x³.y =(5)³.(10)

=1250

8 0
4 years ago
Read 2 more answers
Find the volume of the largest circular cone that can<br> beinscribed in a shpere of radius 3.
Aleksandr [31]

Answer:

V =\dfrac{32}{3}\pi

Step-by-step explanation:

given,

radius of sphere = 3

volume of cone:

V = \dfrac{1}{3}\pi r^2h

r is the radius of circular base

h is the height of the cone

here r = x and h = 3 + y

now, volume in term of x and y

V = \dfrac{1}{3}\pi x^2(3+y)

Applying Pythagoras theorem

x² + y² = 3²

x = \sqrt{9-y^2}

V = \dfrac{1}{3}\pi ( \sqrt{9-y^2})^2(3+y)

V = \dfrac{1}{3}\pi ( 9-y^2)(3+y)

V = \dfrac{1}{3}\pi (27 + 9 y - 3 y^2-y^3)

differentiating both side

\dfrac{dV}{dy} =\dfrac{1}{3}\pi ( 9-6y- 3y^2)

for maxima  \dfrac{dV}{dy} = 0

\pi ( 3-2 y - y^2)=0

 y² + 2 y - 3 = 0

(y+3)(y-1)=0

 y = 1,-3

y cannot be negative so, volume at y = 1

V = \dfrac{1}{3}\pi (27 + 9 (1)- 3(1)^2-(1)^3)

V =\dfrac{32}{3}\pi

Hence, the largest cone which can be inscribed in the spheres of the radius 3 has volume  V =\dfrac{32}{3}\pi

5 0
3 years ago
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