I'm guessing you're saying that the sprinkler is shooting out 23 ft of water.
This would be the same as the radius of a circle, and we're trying to find the area. Use the formula.

Plug in what we know:


This is what they could be looking for, an exact value. If they want an approximation, we can input 3.14 for Pi:

57/19 = 3
x^5 / x^2 = x^(5-2) = <span>x^3
so </span><span>57x^5 / 19x^2 = 3x^3
answer
</span>3x^3
A veriable = 1, use it as with pemdas
Assuming you mean angle ABC and not 2ABC?
Since ray BD bisects angle ABC we can set the two angle measures given equal to each other.
2x+7=4x-41
Solve for x=24
Plug in the x to find angle ABD 2(24)+7=55
therefore angle ABD is 55 and angle DBC is 55 so angle ABC is 110
-13 (q + 4) = 7q + 16
I think to solve it you do this first:
-13q + -52 = 7q + 16
And then I think you do:
-6q + -36
And thats all I can remember sorry ):
Or
That -6q + -36 might be the answer I think (:
Hope I could help (: