The slope-intercept form of a line:
We have:
Substitute:
Put the values of coordinates of the point (1, 5) to the equation of a line:
Answer: 
A straight line needs two pieces of information to be identified, a gradient and a y-intercept (technically any point will do but the y-intercept is particularly convenient if we have it).
The gradient is calculated by taking two points on the line, and dividing the change in y-coordinate by the change in x-coordinate between them. I'm going to take the points (0,-3) and (2,-2).
The change in y-coordinate is (-2) - (-3) = 1
The change in x-coordinate is (2) - (0) = 2.
Gradient = m = 1/2
Next we identify the y-intercept, the value of y when x = 0. This value is -3, and we call it c.
The equation of a line in slope-intercept form is y = mx + c. Slotting in the values for m and c we have ascertained, we find that the equation of this line is:
y = (1/2)x - 3
I hope this helps :)
Answer:
C (- 4, - 2 )
Step-by-step explanation:
(c)
the x- coordinate of A is - 4
the y- coordinate of B is - 2
coordinates of C = (- 4, - 2 )
Working is attached: 2x^3 - 4x^2 + 5x - 6 remainder 3
Answer:
the chemist should use 60 liters of 55% solution and 40 litres of 30% solution in order to prepare 100 liters of 45% purity of sulphuric acid.
Step-by-step explanation:
From the given information,
Let x be the litres of 55% pure solution
Let y be the litres of 30% pure solution
Also;
Given that our total volume of solution is 100 litres
x+y =100 ---- (1)
The total solution of pure by related by the sum of the individual pure concentrations to make up the concentration of final solution.
(0.55)(x)+(0.30)(y) = 0.45(100) ---- (2)
From equation (1)
Let ; y = 100 - x
Replacing the value for y = 100 - x into equation (2)
(0.55)(x)+(0.30)(100-x) = 0.45(100)
0.55x + 30 - 0.30x = 45
0.55x - 0.30x = 45 - 30
0.25x = 15
x = 15/0.25
x = 60 liters of 55% solution
From ; y = 100 - x
y = 100 - 60
y = 40 litres of 30% solution.
Therefore, the chemist should use 60 liters of 55% solution and 40 litres of 30% solution in order to prepare 100 liters of 45% purity of sulphuric acid.
