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sveta [45]
3 years ago
10

Solve the differential equation

d="TexFormula1" title=" \frac{dy}{dx} = 2cos^{2} y" alt=" \frac{dy}{dx} = 2cos^{2} y" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
avanturin [10]3 years ago
5 0

tany =2x+C is the required differential equation.

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Let u = <-6, 1>, v = <-5, 2>. Find -4u + 2v.
34kurt
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-4u = -4*<-6,1>
-4u = <-4*(-6),-4*1>
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----------------------
v = <-5,2>
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