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andrew-mc [135]
2 years ago
5

A line has a slope of -8 and includes the points (-10, 0) and (-9, z). What is the value of Z?

Mathematics
2 answers:
Evgesh-ka [11]2 years ago
6 0

Answer:

Step-by-step explanation:

Let L be the given line, then, with a slope of -8

L :  y = -8x + b

where b is to be determined from the included point A(-10,0).

Substitute point A in L to get

0 = -8 (-10) + b

solve to get

b = -80

therefore

L : y = -8x -80

Now substitute B(-9,z) in L

z = -8(-9) - 80 = -8

Shalnov [3]2 years ago
5 0

Answer:

z = -8

Step-by-step explanation:

Given coordinate points are:

(-10 , 0) = (x1 , y1)

(-9 , z) = (x2 , y2)

slope ( m) = y2-y1/x2-x1

-8 = z - 0/-9 - (-10)

-8 = z/-9 + 10

-8 = z/1

-8*1 = z

-8 = z

therefore the value of z is -8.

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The quantity q varies inversely with the square of m and directly with the product of r and x. When q is 2.5, mis 4 and the
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Answer:

The constant of proportionality is 5.

Step-by-step explanation:

If the quantity q varies inversely with the square of m and directly with the product of r and x, then the variation equation is

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7 0
3 years ago
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A<br><br> B<br><br> C<br><br> Neither of them
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Which equation has a graph that is perpendicular to the graph of -x + 6y = -12?
serious [3.7K]

Answer:

c) 6x + y = -52  is required equation perpendicular to the given equation.

Step-by-step explanation:

If the equation is of the form    : y = mx  + C.

Here m = slope of the equation.

Two equations are said to be perpendicular if the product of their respective slopes is -1.

Here, equation 1 :  -x + 6y = -12

or, 6y = -12  + x

or, y = (x/6)  - 2

⇒Slope of line 1 = (1/6)

Now, for equation 2  to be  perpendicular:

Check for each equation:

a. x + 6y = -67       ⇒  6y = -67  - x

or, y = (-x/6)  - (67/6)      ⇒Slope of line 2 = (-1/6)

but \frac{1}{6} \times \frac{-1}{6}  \neq -1

b. x - 6y = -52   ⇒  -6y = -52  - x

or, y = (x/6)  + (52/6)      ⇒Slope of line 2 = (1/6)

but \frac{1}{6} \times \frac{1}{6}  \neq -1

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or, y =y = -52  - 6x      ⇒Slope of line 2 = (-6)

\frac{1}{6} \times (-6)  =  -1

Hence, 6x + y = -52  is required equation 2.

d. 6x - y = 52  ⇒  -y = 52  - 6x

or, y = 6x   - 52      ⇒Slope of line 2 = (6)

but \frac{1}{6} \times 6  \neq -1

Hence,  6x + y = -52  is  the  only required equation .

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3 years ago
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