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3 years ago

Select the correct answer.

Mathematics

1 answer:

mafiozo [28]3 years ago

5 0

B.The failures of the past should inspire people to accomplish more in the future.

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How do i get a better grade if i'm failing

stellarik [79]

Ask for extra credit.

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3 years ago

Read 2 more answers

The price of a gallon of milk was $2.65. The price rose y dollars after the last hurricane. Then the price dropped $0.15 and lat

elena55 [62]

Answer:

Step-by-step explanation:

So you start with $2.65 and a variable y. What we will do is work without the dollar and keep it for the end as it quite disturbs and work our way while keeping the y. So first we have 2.65. Now it rose by y so. The price = 2.65 + y. Then it dropped by 0.15. So 2.65 + y - 0.15. Here you see we have like terms so we reduce and get 2.50 + y. Now it rose by 0.05. So 2.50 + y + 0.05. Again, like terms, reduce. 2.55 + y. There you go with the answer.

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3 years ago

Marco starts with a population of 10 bacteria that doubles every day for a number of days, d. He writes the expression 10(2d) to

riadik2000 [5.3K]

Answer:

Marco- 10 is the starting value of the population. 2 is the growth rate of "double each day" with d as an exponent.

Isabella- 1 is the starting population. 1+0.2=1.2 is the rate at which it grows each day.

Step-by-step explanation:

Marco's equation should be $10(2^{d})$ since the bacteria double each day. 10 is the starting value of the population. 2 is the growth rate of "double each day" with d as an exponent. This will double each day because:

Day 1 is $2^{1}=2$

Day 2 is $2^{2}=4$

Day 3 is $2^{3}=8$

Day 4 is $2^{4}=16$

You'll notice the value doubles each day.

Isabella has a different equation because her population increases by a percentage. We use the simple interest formula to calculate the bacteria's daily increase or interest.

1(1+0.2)d

1 is the starting population.

1+0.2=1.2 is the rate at which it grows each day.

3 0

4 years ago

Read 2 more answers

How do you do this question?

Lisa [10]

Answer:

Correct integral, third graph

Step-by-step explanation:

Assuming that your answer was 'tan³(θ)/3 + C,' you have the right integral. We would have to solve for the integral using u-substitution. Let's start.

Given : ∫ tan²(θ)sec²(θ)dθ

Applying u-substitution : u = tan(θ),

=> ∫ u²du

Apply the power rule ' ∫ xᵃdx = x^(a+1)/a+1 ' : u^(2+1)/ 2+1

Substitute back u = tan(θ) : tan^2+1(θ)/2+1

Simplify : 1/3tan³(θ)

Hence the integral ' ∫ tan²(θ)sec²(θ)dθ ' = ' 1/3tan³(θ). ' Your solution was rewritten in a different format, but it was the same answer. Now let's move on to the graphing portion. The attachment represents F(θ). f(θ) is an upward facing parabola, so your graph will be the third one.