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krek1111 [17]
3 years ago
11

Which value of a makes the following equation true (x+a)^2=x^2+16x+64

Mathematics
1 answer:
Juliette [100K]3 years ago
8 0

Answer:

The value of a is 8.

Step-by-step explanation:

In the expression, x² + 16x + 64, 64 is a perfect square of 8 so if you factorize it, you will get :

x² + 16x + 64

= x² + 8x + 8x + 64

= x(x + 8) + 8(x + 8)

= (x + 8)²

(x + a)² = (x + 8)²

a = 8

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